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pishuonlain [190]
3 years ago
9

!!HELP PLEASE WILL MARK AS BRAINLIEST!!

Mathematics
1 answer:
Tpy6a [65]3 years ago
5 0
They are parallel when the slopes are the same

example:

y=2x+3
y=2x-5
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Greg and Erin start at the same point and begin running in different directions. Greg is running east at a speed of 7 miles per
AveGali [126]

Answer: The time at which the distance between the two is 150 miles is 1.3 hr.

Step-by-step explanation:

Step 1: Sketch the problem as shown in the attached image.

The problem can be solved using Pythagoras theorem since the sketch is a right angled triangle.

It follows the equation x² + y² = 15².

The distance covered by Greg is given by <em>x mi</em>, and that of Erin is given by <em>y mi</em>.

Step 2: To derive the distance covered by Erin and Greg, we use the formula <em>Speed = distance ÷ time.</em>

Which by cross-multiplying gives <em>distance = speed × time</em>.

Let time taken to cover the distance be <em>t h</em>.

Given that Speed of Erin is 9 mph and that of Greg is 7 mph.

Hence, distance covered by Greg, x = 7 × t = 7t.

Distance covered by Erin, y = 9 × t = 9t.

Step 3: Insert the terms x and y into the Pythagoras equation x² + y² = 15² and solve for <em>time t.</em>

(7t)² + (9t)² = 15²

49t² + 81t² = 225

(49 + 81)t² = 225

      t² = 225/(49 + 81)

      t² = 225/130

      t² = 1.730769231

       t = √1.730769231

       t = 1.315587029

t = 1.3hr

Hence the time at which the distance between the two is 150 miles is 1.3 hr.

4 0
3 years ago
FIRST TO ANSWER GETS BRAINLIEST!
scZoUnD [109]

Answer:

\huge \boxed{ \red{ \boxed{c)78 \: units ^{2} }}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • circle
  • PEMDAS
<h3>tips and formulas:</h3>
  • \rm \:A_{shaded}=  \dfrac{\theta}{360}  \times \pi {r}^{2}
<h3>let's solve:</h3>
  1. \sf sustitute \: the \: value \: of \:  \theta \: and \: r :  \\ A_{shaded} =  \frac{140}{360}  \times \pi \times  {8}^{2}
  2. \sf simpify \: squre :  \\ A_{shaded} =  \frac{140}{360}  \times \pi \times  64
  3. \sf simpify \: fraction:  \\ A_{shaded} =  \frac{7}{18}  \times \pi \times  64
  4. \sf  reduce \: 64:  \\ A_{shaded} =  \frac{7}{ \cancel{ \: 18} \:  ^{9} }  \times \pi \times  \cancel{ 64}  \: ^{32}  \\ A_{shaded} =  \frac{7}{9} \times \pi \times 32\\ A_{shaded} =  \frac{224\pi}{9}

\large A_{shaded}\approx 78 \: square  \: units

8 0
2 years ago
Read 2 more answers
1. if andrew earned 49.50 how many hours did he work?
Alla [95]

Answer:

The picture is black

Step-by-step explanation:

3 0
3 years ago
A tour bus starts from Memphis and heads to Miami at 50 mph. Three hours later a truck pursues the bus at a speed of 65 mph. How
Nina [5.8K]
Three hours after the bus starts out, it's 150 miles ahead of the truck. Then the truck starts out, and it gains (65-50)=15 miles on the bus every hour. If neither of them ever stops for anything, the truck will catch up to the bus in ( 150/15 ) = 10 hours. . . . (The hint is useless.)
7 0
3 years ago
Quadrilateral abcd is a Trapezoid with and area of 20cm find the height of the Trapezoid h round to nearest tenth
Margaret [11]
35 is the answer and dont ask why.

3 0
3 years ago
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