I need help on this question

What are the values of a and b in the equation a[3x-8]=b-18x

3241004551 [841]

A(3x-8)=0

a=0 and x=8/3

This second line is not necessarily true. We could have a=0 OR x=8/3. They don't both have to be 0. a(3x-8)=b-18x

No solutions found

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

a*(3*x-8)-(b-18*x)=0

Step by step solution :

Step 1 :

Equation at the end of step 1 :

a • (3x - 8) - (b - 18x) = 0
Step 2 :

Equation at the end of step 2 :

3ax - 8a + 18x - b = 0
Step 3 :

Solving a Single Variable Equation :

3.1 Solve 3ax-8a+18x-b = 0

3 0

4 years ago

20-x2/y-x for x=2 and y=6

MaRussiya [10]

Use substitution to solve the equation:
20-4/4.
4/4=1 so it simplifies to 20-1 which equals 19

7 0

4 years ago

Read 2 more answers

A computer system uses passwords that are exactly six characters and each character is one of the 26 letters (a–z) or 10 integer

ELEN [110]

Answer:

The number of hits would follow a binomial distribution with $n =10,\!000$ and $p \approx 4.59 \times 10^{-6}$ .

The probability of finding $0$ hits is approximately $0.955$ (or equivalently, approximately $95.5\%$ .)

The mean of the number of hits is approximately $0.0459$ . The variance of the number of hits is approximately $0.0459\!$ (not the same number as the mean.)

Step-by-step explanation:

There are $(26 + 10)^{6} \approx 2.18 \times 10^{9}$ possible passwords in this set. (Approximately two billion possible passwords.)

Each one of the $10^{9}$ randomly-selected passwords would have an approximately $\displaystyle \frac{10,\!000}{2.18 \times 10^{9}}$ chance of matching one of the users' password.

Denote that probability as $p$ :

$p := \displaystyle \frac{10,\!000}{2.18 \times 10^{9}} \approx 4.59 \times 10^{-6}$ .

For any one of the $10^{9}$ randomly-selected passwords, let $1$ denote a hit and $0$ denote no hits. Using that notation, whether a selected password hits would follow a bernoulli distribution with $p \approx 4.59 \times 10^{-6}$ as the likelihood of success.

Sum these $0$ 's and $1$ 's over the set of the $10^{9}$ randomly-selected passwords, and the result would represent the total number of hits.

Assume that these $10^{9}$ randomly-selected passwords are sampled independently with repetition. Whether each selected password hits would be independent from one another.

Hence, the total number of hits would follow a binomial distribution with $n = 10^{9}$ trials (a billion trials) and $p \approx 4.59 \times 10^{-6}$ as the chance of success on any given trial.

The probability of getting no hit would be:

$(1 - p)^{n} \approx 7 \times 10^{-1996} \approx 0$ .

(Since $(1 - p)$ is between $0$ and $1$ , the value of $(1 - p)^{n}$ would approach $0\!$ as the value of $n$ approaches infinity.)

The mean of this binomial distribution would be: $n\cdot p \approx (10^{9}) \times (4.59 \times 10^{-6}) \approx 0.0459$ .

The variance of this binomial distribution would be:

$\begin{aligned}& n \cdot p \cdot (1 - p)\\ & \approx(10^{9}) \times (4.59 \times 10^{-6}) \times (1- 4.59 \times 10^{-6})\\ &\approx 4.59 \times 10^{-6}\end{aligned}$ .

4 0

3 years ago

Tell me something to watch your girl do be bored...

Fittoniya [83]

Answer:

ᴡᴀᴛᴄʜ sᴏᴍᴇ ᴍᴜsɪᴄ ᴠɪᴅᴇᴏs...ᵗʰᵃᵗ ⁱˢ ʷʰᵃᵗ ⁱ ʷᵃᵗᶜʰ ʷʰᵉⁿ ⁱ ᵍᵉᵗ ᵇᵒʳᵉᵈ...ᵐᵒˢᵗˡʸ ᵏᵖᵒᵖ

<h2>ᴋᴅʀᴀᴍᴀ ʟɪsᴛ ᵐʸ ᶠᵃᵛˢ :</h2>

ʜᴏᴛᴇʟ ᴅᴇʟ ʟᴜɴᴀ

ɪᴛ ɪs ᴏᴋᴀʏ ᴛᴏ ɴᴏᴛ ʙᴇ ᴏᴋᴀʏ

ʜᴡᴀʀᴀɴɢ

ᴄʀᴀsʜ ʟᴀɴᴅɪɴɢ ᴡɪᴛʜ ʏᴏᴜ

ᴘᴇɴᴛʜᴏᴜsᴇ

$\infty \infty$

8 0

3 years ago

How do i graph this step function? f(x)=[[3x]]+3

puteri [66]

One way is shown here: https://www.desmos.com/calculator/76qirhx3nh
___
A step function is defined various ways. One way has [[0]] = 1/2. That is what is shown on the graph at the above link. Choose the definition that matches your text.

The horizontal scale factor of 3 (in 3x) does nothing. When x > 0, 3x > 0; when x < 0, 3x < 0. The +3 adds a vertical offset to the graph of [[x]].

6 0

3 years ago