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2 years ago

The area of the polygon shown in the figure is _______.

Mathematics

1 answer:

QveST [7]2 years ago

5 0

The answer is 72 Reasoning being that the problem is A length times width situation so 8x9=72

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4. What method can be use to prove the triangles below are congruent?

lutik1710 [3]

Answer:

congruent by Angle Angle Side (AAS)

If my answer is right then please follow me 

need followers :-)

6 0

3 years ago

What is the difference between advanced calculus and real analysis?

eduard

The content of any course depends on where you take it--- even two courses with the title "real analysis" at different schools can cover different material (or the same material, but at different levels of depth).

But yeah, generally speaking, "real analysis" and "advanced calculus" are synonyms. Schools never offer courses with *both* names, and whichever one they do offer, it is probably a class that covers the subject matter of calculus, but in a way that emphasizes the logical structure of the material (in particular, precise definitions and proofs) over just doing calculation.

My impression is that "advanced calculus" is an "older" name for this topic, and that "real analysis" is a somewhat "newer" name for the same topic. At least, most textbooks currently written in this area seem to have titles with "real analysis" in them, and titles including the phrase "advanced calculus" are less common. (There are a number of popular books with "advanced calculus" in the title, but all of the ones I've seen or used are reprints/updates of books originally written decades ago.)

There have been similar shifts in other course names. What is mostly called "complex analysis" now in course titles and textbooks, used to be called "function theory" (sometimes "analytic function theory" or "complex function theory"), or "complex variables". You still see some courses and textbooks with "variables" in the title, but like "advanced calculus", it seems to be on the way out, and not on the way in. The trend seems to be toward "complex analysis." hope it helps

8 0

4 years ago

Help me out big bois

BaLLatris [955]

It’s 78-45 to get the new season

8 0

3 years ago

Consider a cylinder with a diameter of 14 centimeters and a height of h centimeters. Which equation can be used to find V, the v

goldenfox [79]

Answer:

Step-by-step explanation:

Diameter of the cylinder = 14 centimeters

to find the radius divide the diameter by 2

Radius of the cylinder = 14/2 = 7 centimeters

Volume of the cylinder = V = πr² h

to solve it =

V = 22/7 × 7² × h

the equation is V = (22/7 × 7² × h)cm³

in solving it will be V = 22/7 × 49h

V = 1078/7

V = 154cm²

8 0

4 years ago

A tank contains 9,000 L of brine with 18 kg of dissolved salt. Pure water enters the tank at a rate of 90 L/min. The solution is

aev [14]

Let x(t) denote the amount of salt (in kg) in the tank at time t. The tank starts with 18 kg of salt, so x (0) = 18.

The solution is drained from the tank at a rate of 90 L/min, so that the amount of salt in the tank changes according to the differential equation

dx(t)/dt = - (x(t) kg)/(9000 L) × (90 L/min) = -1/100 x(t) kg/min

or, more succintly,

x' = -1/100 x

This equation is separable as

dx/x = -1/100 dt

Integrating both sides gives

∫ dx/x = -1/100 ∫ dt

ln|x| = -1/100 t + C

x = exp(-1/100 t + C )

x = C exp(-t/100)

(a) Using the initial condition x (0) = 18, we find

18 = C exp(0) ==> C = 18

so that

x(t) = 18 exp(-t/100)

(b) After 20 minutes, we have

x (20) = 18 exp(-20/100) = 18 exp(-1/5) ≈ 14.74

so the tank contains approximately 14.74 kg of salt after this time.

7 0

3 years ago