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Olin [163]
2 years ago
8

Find the limit (Picture Provided)

Mathematics
2 answers:
aev [14]2 years ago
8 0

As long as g(x) (or whichever function appears in the denominator) does not approach 0 as x\to c,

\displaystyle\lim_{x\to c}\frac{f(x)}{g(x)}=\frac{\lim\limits_{x\to c}f(x)}{\lim\limits_{x\to c}g(x)}

In this case,

\displaystyle\lim_{x\to4}\frac gh(x)=\lim_{x\to4}\frac{g(x)}{h(x)}=\frac0{-2}=2

so the answer is B.

nadya68 [22]2 years ago
3 0

ANSWER

b. 0

EXPLANATION

We use the property of limits;

lim_{x\to 4} \frac{g}{h} (x) = lim_{x\to 4} \frac{g(x)}{h(x)}

lim_{x\to 4} \frac{g}{h} (x) =  \frac{lim_{x\to 4}g(x)}{lim_{x\to 4}h(x)}

Substitute,

lim_{x\to 4} \frac{g}{h} (x) =  \frac{0}{ - 2}

Simplify;

lim_{x\to 4} \frac{g}{h} (x) =0

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The base of trapezoid is 31 in and 16 in, and the height is 35 - 20 = 15 in.
a₂ = 1/2 × (a + b) × h
a₂ = 1/2 × (31 + 16) × 15
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Find the area of the triangle
The base of the triangle is 31 in, the height is 20 in
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Have a good day
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