Answer:
If one buoy is placed 120 feet away from the left shore, then the distance of the second buoy from the left shore = 480
Step-by-step explanation:
Given that:
The absolute value function:

To calculate the position of the buoy where the river bottom is 20 feet below the surface, we equate the absolute value function to the negative value of 20 feet and then solve it for h.
d(h) = -20

Let us add the sum of 50 on both sides, then:


By multiplying 6 on both sides, we have:
|h - 300| = 30 (6)
|h - 300| = 180
We can attempt the above expression by rewriting it as two equations:
h - 300 = 180 or h - 300 = - 180
Let us add 300 to both sides from the two expressions above:
h - 300 + 300 = 180 + 300 or h - 300 + 300 = -180 + 300
h = 480 or h = 120
Thus, if one buoy is placed 120 feet away from the left shore, then the distance of the second buoy from the left shore = 480
Answer;
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Step-by-step explanation:
divide each term by y then simplify
X<12
<span>5(x+5)<85 </span>
<span>5(x + 5)/5 < 85/5 </span>
<span>x + 5 < 17 </span>
<span>x + 5 - 5 < 17 - 5</span>
Given that Bill
is on the school archery team. the target has a center bull's-eye and
two rings around the bull's-eye.
Given the table below that gives the probabilities of outcomes.

The probability <span>that Bill will get the next arrow in the inner or outer ring is given by
P(inner ring) + P(outer ring) = 0.297 + 0.423 = 0.72</span>
Therefore, <span>the probability that Bill will get the next arrow in the inner or outer ring is 0.72</span>
Answer:
C
Step-by-step explanation:
I think it is C. Sorry if I'm wrong.