Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.
1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.
According to this theorem,
Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then
Take positive value x. You get
2. According to the previous theorem,
Then
Answer: 
This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then
This means that you cannot find solutions of this equation. Then CD≠2 cm.
Answer:
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Step-by-step explanation:
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Answer:
(b) angle FOA
(c) angle EOA
(d) angle AOH
Step-by-step explanation:
(b) The rays of vertical angles are opposites that form intersecting lines.
The opposite of ray OG is OF. The opposite of ray OB is OA, so the vertical angle to GOB is angle FOA.
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(c) The opposite of ray OB is OA, so the supplement to angle EOB is angle EOA.
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(d) Similarly, the supplement to angle BOH is angle AOH.
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<em>Comment on supplementary angles</em>
Angles that form a linear pair are supplementary. Angles do not have to form a linear pair to be supplementary. They merely have to have a sum of 180°. Here, the supplementary angles of interest do form a linear pair, so finding the other angle of the pair means only finding the other point that names the line being formed by the pair.
Answer:
1. a=3, b = 2, c = 1.
2. a=2, b=3, c=4, d=6.
3. a = 9, b = 3.
Step-by-step explanation:
1. 3 | 21 is a counterexample because 3 does not divide into 2 or 1.
2. 23 | 46 is a counterexample because 2 does not divide into 3.
3. 9 | 3^2 is a counterexample because 9 does not divide into 3.
