Answer:
y=1/4x+1.5
Step-by-step explanation:
Slope is 1/4 and I figured out that the y-intercept point is 1.5y.
I am not exactly sure though
Complete question is;
Components arriving at a distributor are checked for defects by two different inspectors (each component is checked by both inspectors). The first inspector detects 83% of all defectives that are present, and the second inspector does likewise. At least one inspector does not detect a defect on 34% of all defective components. What is the probability that the following occurs?
(a) A defective component will be detected only by the first inspector?
b) A defective component will be detected by exactly one of the two inspectors?
(c) All three defective components in a batch escape detection by both inspectors (assuming inspections of different components are independent of one another)?
Answer:
A) 0.17
B) 0.34
C) 0
Step-by-step explanation:
a) We are told that the first inspector(A) detects 83% of all defectives that are present, and the second inspector(B) also does the same.
This means that;
P(A) = P(B) = 83% = 0.83
We are also told that at least one inspector does not detect a defect on 34% of all defective components.
Thus;
P(A' ⋃ B') = 0.34
Also, we now that;
P(A ⋂ B) = 1 - P(A' ⋃ B')
P(A ⋂ B) = 1 - 0.34
P(A ⋂ B) = 0.66
Probability that A defective component will be detected only by the first inspector is;
P(A ⋂ B') = P(A) - P(A ⋂ B)
P(A ⋂ B') = 0.83 - 0.66
P(A ⋂ B') = 0.17
B) probability that a defective component will be detected by exactly one of the two inspectors is given as;
P(A ⋂ B') + P(A' ⋂ B) = P(A) + P(B) - 2P(A ⋂ B)
P(A) + P(B) - 2P(A ⋂ B) ; 0.83 + 0.83 - 2(0.66) = 0.34
C) Probability that All three defective components in a batch escape detection by both inspectors is written as;
P(A' ⋃ B') - (P(A ⋂ B') + P(A' ⋂ B))
Plugging in the relevant values, we have;
0.34 - 0.34 = 0
I dont have options but i can sayEach of these questions is asking you to figure out how g(x) would be graphed based on some other function, f(x), except we're gonna make some changes to f(x) first. For example, let's look at part (a). You're told that g(x) = 2f(x)+3. 1. Whatever f(x) is, 2f(x) would take all of the y values and double them.2. Whatever that turns out to be, "+3" would add 3 to every y value. So, to translate (1, -2), first we double the y value...so that'd be -2 * 2, or -4. Then we add 3, which gives 1. So, the point (1, -2) becomes (1, 1). [EDIT: Um, no, -4 + 1 isn't 1. It's -1. My bad! MBW] Part (b) is a little bit trickier: 1. Whatever f(x) is, by adding 1 to x, it actually shifts the graph left by 1, even though it sorta feels like you should be shifting it 1 to the right. Let's not get too far into the details here, so for the moment, f(x+1) means "shift the graph of f to the left by 1." In other words, subtract 1 from x to get the new point. 2. Whatever f(x+1) is, then the "-3" would subtract 3 to every y value. So, if (1, -2) was on the original graph, then f(x+1) would be shifted to the left by 1...so that's (0, -2). And then, we subtract 3 from y, so that'd be (0, -5). Basically, anything inside the parentheses, like f(x+1), messes with the x coordinate of the point, and anything outside the parentheses, like -f(x) or f(x) + 3, messes with the y coordinate. For the last two, I'll give you a few hints and see if you can take it from there. For part (c): f(2x), even though you think it might double the value of x, actually divides the value of x by 2.For part (d): the trick here is to ignore the "-x" until the last step. Deal with the f(x-1) first (which shifts the x coordinate...which way?), then the negative outside of f(x) (which flips the sign of the y coordinate), then the +3 outside of f(x)...and then, at the end, the "-x" would flip the sign of the x coordinate. I hope this helps point you in the right direction!
There are 13 diamonds, and 4*3=12 face cards, of which 3 are diamonds.
So total of "diamond or face card" is 13+12-3=22.
=>
Probability of drawing a diamond OR a face card from a full 52-card deck is
22/52=11/26.
