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3 years ago

3 1/4 as an improper fraction

Mathematics

2 answers:

Sedbober [7]3 years ago

7 0

You do 3 times 4 plus 1 and that's 13/4.

Snowcat [4.5K]3 years ago

7 0

3 1/4 as an improper fraction is 13/4 (multiply denominator by whole number then add numerator, if there are ever negatives, leave them until you have the answer)

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A large bacterium measures 750 micrometers in diameter. One micrometer = 10 − 6 meters. How would you express the diameter of th

ANEK [815]

Answer:

7.5 * 10^-4

Step-by-step explanation:

To express this, we will have to multiply 750 by the conversion unit

we have this as;

750 * 10^-6

750 = 7.5 * 10^2

so we have;

7.5 * 10^2 * 10^-6

= 7.5 * 10^(-6+2)

= 7.5 * 10^-4

7 0

3 years ago

last night, julie's pet hamster zoe kept julie awake for at least an hour running on her exercise wheel and scratching at the co

borishaifa [10]

Answer: $x+y\geq 1$ , $x>\frac{1}{4}$ , $x\geq 2y$ and $y\geq 0$

Step-by-step explanation:

Here, x represents the number of hours Zoe spent running on her wheel and y represents the number of hours spent scratching her cage.

Julie was awoke for at least an hour running on her exercise wheel and scratching the of her cage.

⇒ $x+y\geq 1$

She ran on her wheel at least twice as long as she scratched at the corners of her cage.

⇒ $x\geq 2y$

Also, She spent more than 1/4 hour running on her wheel.

⇒ $x>\frac{1}{4}$

And, we know that number of hours can not be negative.

⇒ $y\geq 0$

Therefore, the complete system of inequality which shows the given situation is,

$x+y\geq 1$ , $x>\frac{1}{4}$ and $x\geq 2y$ , $y\geq 0$

Note: the feasible region ( covered by the given system) is shown in the below graph.

6 0

3 years ago

Convert 7/20 to a percent

Wewaii [24]

♥ To start you are going to divide $\frac{7}{20}$

♥ Solve:
$0.35$

♥ Now multiply this by 100.
$0.35*100$

♥ Solve:
35

♥ Now you have your final answer: 35%

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3 years ago

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TEA [102]

Part a y=95x

Part b 285=95•3

Part c ?

Hope I helped sorry I don't know how to do the last one!

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3 years ago

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Consider the following linear programming problem.

givi [52]

Answer: