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zhenek [66]
2 years ago
7

Identify the domain and range of the relation.

Mathematics
1 answer:
kondor19780726 [428]2 years ago
6 0

Answer:

Domain: -5, -2, 1, 5

Range: 10, 11, 4, 10

To get the function, you need to create an equation.

Step-by-step explanation:

For example, f(x)= 10x. "x" equals your y value, and "10" is where you plug in your range, or in other words, your y-values.

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Complete the following statement. Round to the nearest hundredth .
RSB [31]

f(x) = 3/(x + 2) - √x - 3

f(7) = 3/(7 + 2) - √7 - 3

f(7) = 3/9 - √4

f(7) = 0.333 - 2

f(7) = -1.67

7 0
2 years ago
Please help! Thank you
Alex_Xolod [135]
Find the future value
A=p (1+r/k)^kt
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A=4,581.72
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Use the model below to write and solve equation
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Answer is:

X is 1, very simple

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Complete the sentence to make it true statements 6 is 100 times
AnnyKZ [126]

Answer:

6 is 100 times 0.06

Step-by-step explanation:

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Create a matrix that is equal to F+G. The first matrix below is named F and the second matrix below is named G. Name the new mat
likoan [24]

F+G:

F+G=\begin{bmatrix}{-1.8} & {-8.6} & {} \\ {2.85} & {-1.4} & {} \\ {-1.8} & {5.1} & {}\end{bmatrix}+\begin{bmatrix}{1.32} & {-1.9} & {} \\ {2.25} & {0.0} & {} \\ {-6.2} & {1.4} & {}\end{bmatrix}

Then, add the elements that occupy the same position:

H=\begin{bmatrix}{-1.8+1.32} & {-8.6+(-1.9)} & {} \\ {2.85+2.25} & {-1.4+0.0} & {} \\ {-1.8+(-6.2)} & {5.1+1.4} & {}\end{bmatrix}

Solve

H=\begin{bmatrix}{-0.48} & {-10.5} & {} \\ {5.1} & {-1.4} & {} \\ {-8} & {6.5} & {}\end{bmatrix}

So, we find the element at address h31:

H=\begin{bmatrix}{h11} & {h12} & {} \\ {h21} & {h22} & {} \\ {h31} & {h32} & {}\end{bmatrix}

In this case, position h31 is - 8.0

8 0
1 year ago
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