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3 years ago

Someone help me solve this problem

Mathematics

1 answer:

katrin [286]3 years ago

3 0

Same-side interior angles where a transversal crosses parallel lines are supplementary:

6y +4y = 180
90 +5x = 180

The solutions to these equations can probably be done in your head:

y = 180/(6+4) = 18
x = (180-90)/5 = 18

The angles at the bottom of the figure, shown as different, are actually the same: 90°.

The angles at the top of the figure, shown as the same, are actually different: 108° on the left, 72° on the right.

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The lines in the figure are lines XV and YZ.

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Wouldn't that be 108

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cert 22.2 U To 3. Draw an area diagram to find (0.36) (0.53). Label and organize your work so that it can be followed by others.

Masteriza [31]

The result of the product of (0.36) and (0.53) is 0.1908

<h3>How to determine the product</h3>

The product expression is given as:

(0.36) * (0.53)

Rewrite the product as follows:

$(0.36) * (0.53) = (0.3 + 0.06) * (0.5 + 0.03)$

Expand the product

$(0.36) * (0.53) = 0.3 * (0.5 + 0.03)+ 0.06 * (0.5 + 0.03)$

Expand

$(0.36) * (0.53) = 0.15 + 0.009+ 0.03+ 0.0018$

Evaluate the sum

$(0.36) * (0.53) = 0.1908$

See attachment for the area diagram of the product

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brainly.com/question/10873737

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1 year ago

Mr. Monasterio ran to the store for burritos at 4 miles per hour. On the way back, he increased his speed to 6 miles per hour. I

sveticcg [70]

Answer:

It took 1.2 hours to get to the store

Step-by-step explanation:

Let the time taken to reach the store be t₁

Let the time taken to come back be t₂

Let the speed to and from store = s₁ and s₂ respectively

let the distance to the store = d

To the store:

$speed = \frac{distance}{time} \\s = \frac{d}{t_1} \\t_1 = \frac{d}{s_1}\\t_1 =\frac{d}{4} - - - - - (1)$

Back from the store:

$s_2 = \frac{d}{t_2} \\t_2 = \frac{d}{s_2}\\where:\\s_2 = 6\ miles\ per\ hour\\t_2 = \frac{d}{6} - - - - - - (2)$

We are told that total time (t₁ + t₂) = 2 hours

t₁ + t₂ = eqn (1) + eqn (2)

$\frac{d}{4} + \frac{d}{6} = 2\\Multiplying\ through\ by\ 12:\\3d\ +\ 2d\ =\ 24\\5d = 24\\d = \frac{24}{5} \\d = 4.8\ miles$

∴ length of trip to the store = t₁

from eqn (1)

$t_1 = \frac{d}{4} \\t_1 = \frac{4.8}{4} \\t_1 = 1.2\ hours$

7 0

3 years ago