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3 years ago

15

The cheerleading squad is making posters. They have 3 different colors of poster board and 4 different colors of markers. How ma

ny different posters can be made by using one poster board and one marker? plus how do you work it out

1 answer:

satela [25.4K]3 years ago

3 0

12 different boards can be made
1 marker can go on 3 different posters and their are 4 markers so 3 times 4 equals 12

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Which ordered pair is a solution to the equation? -7x+3y=2

Reptile [31]

Answer:

(-7, 3) i think, not 100% sure

Step-by-step explanation:

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3 years ago

Read 2 more answers

Maria mixes \frac{1}{4} cup white sugar and \frac{2}{3} cup brown sugar to make a topping for some muffins. She uses \frac{1}{12

Hoochie [10]

Answer: 11 muffins

Step-by-step explanation:

Since Maria mixes 1/4 cup white sugar with 2/3 cup brown sugar, this will give us a mixture of:

= 1/4 + 2/3

= 3/12 + 8/12

= 11/12

Ww are then told that she uses 1/12 cup of the mixture to top each muffin. Therefore, the number of muffins that she can top will be:

= 11/12 ÷ 1/12

= 11/12 × 12/1

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3 years ago

If there are 6 serving in a 2/3 pound lb package of pound is in each serving

Serhud [2]

Answer:

$\boxed{\math{\frac{1}{9}\text{ lb}}}$

Step-by-step explanation:

$\text{Size of one serving} = \dfrac{\text{Total size}}{\text{No of servings}} = \dfrac{\frac{2}{3}\text{ lb}}{\text{6 servings}}\\\\\text{Change the 6 to a fraction and change divide to multiply}\\\\\dfrac{2}{3} \div 6 = \dfrac{2}{3} \times \dfrac{1}{6}$

$\text{Cancel the 2s}\\\\\dfrac{2}{3} \times \dfrac{1}{6} = \dfrac{1}{3} \times \dfrac{1}{3}\\\\\text{Multiply numerators and denominators}\\\\\dfrac{1}{3} \times \dfrac{1}{3} = \dfrac{1}{9}\\\\\text{Each serving contains }\boxed{\mathbf{\frac{1}{9}\textbf{ lb}}}$

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3 years ago

Find the value of x. 64 x

lions [1.4K]

Answer:

the value of x is 116

Step-by-step explanation:

180-64=116

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3 years ago

Question 3 (4 MARKS) Find the equation of the tangents to the curve of the function with rule y = x^2 at the points where x = a

Arte-miy333 [17]

Answer:

(0 , -a²)

Step-by-step explanation:

tangent at x = a and x = -a

y = x² (a , a²) and (-a , a²) must be on the curve and tangent to curve

gradient dy/dx = 2x

slope (m) at x = a is <u>2a</u> and slope (m') at x=-a is<u> -2a</u>

line1: (y - a²) / (x - a) = 2a

y - a² = 2a (x - a) y = 2ax - a² ... (1)

line2: (y - a²) / (x + a) = - 2a y = -2ax- a² ... (2)

(1) - (2): 4ax = 0 a≠0 x = 0

y = - a²

I wish I did it right, or ....

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3 years ago