Answer:
∠ RQS = 138°
Step-by-step explanation:
Since PR and PS are tangents to the circle, then
∠ QRP = ∠ QSP = 90°
The sum of the interior angles of PRQS = 360°
Subtract the sum of the interior angles from 360° for ∠ RQS
∠ RQS = 360° - (90 + 90 + 42)° = 360° - 222° = 138°
5x^2+6=f(x)
and your graph plug that equation into an graph creator and it will automaticlly make your graph
Perimeter of quadrilateral ANCM = AN+NC+CM+MA
CM=AM = x in
Therefore, AN=NC = x in
In other words, all sides of the new quadrilateral are equal.
Perimeter (P) = 4x in
Now, Cos 45 = (x-6)/x =>0.7041 = (x-6)/x => 0.7041x=x-6 =>x= 6/(1-0.70741)
x= 20.5 in
Therefore, P=4*20.5 = 82 in
Answer:
∠Q = 75°
Step-by-step explanation:
Start by recognizing that the triangle is isosceles (the long sides are marked as being equal-length). That means angles Q and R have the same measure.
Next, you use the fact that the sum of angles is 180° to write an equation.
∠R +∠P +∠Q = 180°
(2x +15)° +x° +(2x +15)° = 180° . . . . substitute the known values
5x +30 = 180 . . . . . . . . . . . . . . . . divide by °, collect terms
5x = 150 . . . . . . . . subtract 30
x = 30 . . . . . . . divide by 5
Then angle Q is ...
∠Q = (2x +15)° = (2×30 +15)°
∠Q = 75°
Answer:
Each book cost $12.50 dollars.
Step-by-step explanation:
1,187.50 / 95 = 12.50