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kogti [31]
3 years ago
15

The cheerleading squad is making posters. They have 3 different colors of poster board and 4 different colors of markers. How ma

ny different posters can be made by using one poster board and one marker? plus how do you work it out
Mathematics
1 answer:
satela [25.4K]3 years ago
3 0
12 different boards can be made
1 marker can go on 3 different posters and their are 4 markers so 3 times 4 equals 12
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And question 2 is use your knowledge of central and inscribed angles to find M.
ivanzaharov [21]

Answer:

∠ RQS = 138°

Step-by-step explanation:

Since PR and PS are tangents to the circle, then

∠ QRP = ∠ QSP = 90°

The sum of the interior angles of PRQS = 360°

Subtract the sum of the interior angles from 360° for ∠ RQS

∠ RQS = 360° - (90 + 90 + 42)° = 360° - 222° = 138°

7 0
3 years ago
SOMEBODY PLEASE HELP ME! IM BEGGING YOU! I MIGHT FAIL ALGEBRA 1 AND HAVE TO REDO 8TH GRADE!! PLEASE JUST HELP ME!!!
Misha Larkins [42]
5x^2+6=f(x)

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3 years ago
In rectangle ABCD, the angle bisector of ∠A intersects side DC at point M and the angle bisector of ∠C intersects side AB at poi
Verizon [17]
Perimeter of quadrilateral ANCM = AN+NC+CM+MA

CM=AM = x in
Therefore, AN=NC = x in
In other words, all sides of the new quadrilateral are equal.

Perimeter (P) = 4x in

Now, Cos 45 = (x-6)/x =>0.7041 = (x-6)/x => 0.7041x=x-6 =>x= 6/(1-0.70741)
x= 20.5 in

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7 0
3 years ago
I don’t know how to solve for Q.
Naya [18.7K]

Answer:

  ∠Q = 75°

Step-by-step explanation:

Start by recognizing that the triangle is isosceles (the long sides are marked as being equal-length). That means angles Q and R have the same measure.

Next, you use the fact that the sum of angles is 180° to write an equation.

  ∠R +∠P +∠Q = 180°

  (2x +15)° +x° +(2x +15)° = 180° . . . . substitute the known values

  5x +30 = 180 . . . . . . . . . . . . . . . . divide by °, collect terms

  5x = 150 . . . . . . . . subtract 30

  x = 30 . . . . . . . divide by 5

Then angle Q is ...

  ∠Q = (2x +15)° = (2×30 +15)°

  ∠Q = 75°

8 0
2 years ago
Northside Middle School spent $1187.50 on<br> 95 math books. How much did each book<br> cost?
trasher [3.6K]

Answer:

Each book cost $12.50 dollars.

Step-by-step explanation:

1,187.50 / 95 = 12.50

6 0
3 years ago
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