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kozerog [31]
3 years ago
13

PLEASE HELP QUICK!!!

Mathematics
1 answer:
kap26 [50]3 years ago
4 0
In this question, you are given the plane 1 speed(496miles/h), plane1 depart time(8:00), plane 2 speed(558miles/h) and plane2 depart time(8:30 or 8.5 hour). Both of the planes left from the same airport so their traveling distance should be same. They also arrive in same time. Then the equation would be:

duration = arriving time - depart time
duration1= x= arriving time - 8h
duration2= y= arriving time -8.5h= (arriving time - 8h) -0.5h= x-0.5h 

speed1 * duration1 = speed2 * duration2
496 * x = 558* (x-0.5)
496x = 558x - 279
279= 558x- 496x
279= 62x
x= 4.5hour 
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Y=x-5; domain = {4,6,8}
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Answer:

Range = {-1, 1, 3}

Step-by-step explanation:

<u><em>The question asks for the range.</em></u>

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y=x-5

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We need to find the range.

First, the range is the set of all y-values for which the function is defined.

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So, we evaluate the function (y-values) at x = 4,6, and 8.

At x = 4:

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At x = 8:

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Thus, the range is:

Range = {-1, 1, 3}

7 0
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