PLEASE HELP QUICK!!!

1 answer:

4 0

In this question, you are given the plane 1 speed(496miles/h), plane1 depart time(8:00), plane 2 speed(558miles/h) and plane2 depart time(8:30 or 8.5 hour). Both of the planes left from the same airport so their traveling distance should be same. They also arrive in same time. Then the equation would be:

duration = arriving time - depart time
duration1= x= arriving time - 8h
duration2= y= arriving time -8.5h= (arriving time - 8h) -0.5h= x-0.5h

speed1 * duration1 = speed2 * duration2
496 * x = 558* (x-0.5)
496x = 558x - 279
279= 558x- 496x
279= 62x
x= 4.5hour

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Shondra buys a bedroom suite on the in-stallment plan. She makes a down payment of $200 and monthly payments of $52 each for thr

Dmitry [639]

Answer:

$2072

Step-by-step explanation:

Note that:

1 year = 12 months

Hence:

1 year = 12 months

3 years = x months

Cross Multiply

x = 3 × 12

x = 36 months

She makes a down payment of $200 and monthly payments of $52 each for three years.

Her total cost is represented by the expression

= $200 + $52 × m

Where m = number of monthly payments.

$200 + $52 × 36

= $200 + $1872

= $ 2072

7 0

3 years ago

Write an equation in point slope form for the line that passes through (-5,6) and (-3,-9).

Finger [1]

$\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{6})\qquad
(\stackrel{x_2}{-3}~,~\stackrel{y_2}{-9})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-9-6}{-3-(-5)}\implies \cfrac{-9-6}{-3+5}\implies -\cfrac{15}{2}$

$\bf \begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-6=-\cfrac{15}{2}[x-(-5)]\implies y-6=-\cfrac{15}{2}(x+5)
\\\\\\
y-6=-\cfrac{15}{2}x-\cfrac{75}{2}\implies y=-\cfrac{15}{2}x-\cfrac{75}{2}-6\implies y=-\cfrac{15}{2}x-\cfrac{87}{2}$