Question

Andrew has 212 coins, all of

Answer 1

Answer:

158 quarters

54 dimes

Step-by-step explanation:

Let d = no. of dimes

     q = no. of quarters

10d = value of all the dimes since each dime is worth 10 cents

and 25q = value of all the quarters since each quarter is worth 25 cents

$44.90 = 4490 cents

  10d + 25q = 4490              d + q = 212

- 10d - 10q = -2120

             15q = 2370

                 q = 158 quarters   d + 158 = 212

                                                        d = 54 dimes