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Svetllana [295]
3 years ago
12

Two factory plants are making TV panels. Yesterday, Plant A produced 3 times as many panels as Plant B. Three percent of the pan

els from Plant A and 4% of the panels from Plant B were defective. How many panels did Plant A produce, if the two plants together produced 1300 defective panels?
Mathematics
1 answer:
mart [117]3 years ago
8 0
Let us assume the number of panels produced by Plant A = z
Let us assume the number of panels produced by Plant B = y
Then
x = 3y
0.03x + 0.04y = 1300
Multiplying both sides of the second equation by 100, we get
3x + 4y = 130000
Putting the value of x from the first equation in the second equation, we get
3x + 4y = 130000
3(3y) + 4y = 130000
13y = 130000
y = 10000
Then
x = 3 * 10000
   = 30000
From the above deduction, we can conclude that the number of panels made by Plant A is 30000.
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Answer:

(4,0) and (- 2,0): Answer

Step-by-step explanation:

Absolute value questions have two essential steps.

1. Solve the equation as it is written.

2. Solve it changing the sign of the right hand side. I will include a graph to confirm my answer

4*abs(x - 1) = 12             Divide by 4

  • abs(x - 1) = 12/4            
  • abs(x - 1) = 3                  Equate this to 3
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4*abs(x - 1) = - 12         Divide by 4

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So this has 2 answers

(4,0) and (- 2,0)

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