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3 years ago

8

Help 10 points Is the most it allowed me to put so yeah but still need help. What number is missing from this factor tree for th

e prime factorization of 525?
____*105
5*21
3*7
A. 2
B. 3
C. 5
D. 7

1 answer:

valentinak56 [21]3 years ago

8 0

C. 5 because 525/5 is 105

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Please help asap, will mark Brainliest xoxo

IgorC [24]

Answer/Step-by-step explanation:

Given, $b(x) = (\frac{6}{7})^{x}$

The table for the function are:

When x = -2

$b(-2) = (\frac{6}{7})^{-2}$

$b(-2) = \frac{1}{(\frac{6}{7})^{2}}$

$b(-2) = \frac{1}{(\frac{36}{49})}$

$b(-2) = 1*\frac{49}{36}$

$b(-2) = \frac{49}{36}$

When x = -1

$b(-1) = (\frac{6}{7})^{-1}$

$b(-1) = \frac{1}{(\frac{6}{7})}$

$b(-1) = 1*\frac{7}{6}$

$b(-2) = \frac{7}{6}$

When x = 0

$b(0) = (\frac{6}{7})^{0}$

$b(0) = \frac{6^0}{7^0}$

$b(0) = \frac{1}{1}$

$b(0) = 1$

When x = 1

$b(1) = (\frac{6}{7})^{1}$

$b(1) = \frac{6}{7}$

When x = 2

$b(2) = (\frac{6}{7})^{2}$

$b(2) = \frac{6^2}{7^2}$

$b(2) = \frac{36}{49}$

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