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Korolek [52]
2 years ago
5

the soccer league needs to transport all 133 players to the tournament. If 4 players can ride in one car, how many cars are need

ed?
Mathematics
2 answers:
LenKa [72]2 years ago
5 0

Take the 133 players and divide by 4.

         (133 / 4) = 33.25

33 cars can carry   (33 x 4) = 132 players.
But that leaves one player out in the cold with no ride.
You need one more car ... 34 cars all together.
kiruha [24]2 years ago
4 0
Just divide 133 by 4 and that's going to get your answer which is 33.25
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3x+4y =-5<br> 3x+3y=-2<br><br> solve using substitution
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Help me answer please
fiasKO [112]

Answer:

25

Step-by-step explanation:

b=4x+1    h=x+1     A=175

A=bh

Substitute: 175=(4x+1)(x+1)

Expand: 175=4x^2+5x+1

Subtract 175

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6 0
2 years ago
The 2003 Zagat Restaurant Survey provides food, decor, and service ratings for some of the top restaurants across the United Sta
earnstyle [38]

Answer:

The probability that none of the meals will exceed the cost covered by your company is 0.2637.

Step-by-step explanation:

A hyper-geometric distribution is used to define the probability distribution of <em>k</em> success in <em>n</em> samples drawn from a population of size <em>N</em> which include <em>K</em> success. Every draw is either a success of failure.

The random variable <em>X</em> = number of meals that will exceed the cost covered by the company.

The random variable <em>X</em> follows a hyper-geometric distribution.

The information provided is:

N = 15

K = 3

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The probability mass function of a hyper-geometric distribution is:

P(X=k)=\frac{{K\choose k}{N-K\choose n-k}}{{N\choose n}}

Compute the probability that none of the meals will exceed the cost covered by your company as follows:

P(X=0)=\frac{{3\choose 0}{15-3\choose 5-0}}{{15\choose 5}}=\frac{1\times 792}{3003}=0.2637

Thus, the probability that none of the meals will exceed the cost covered by your company is 0.2637.

3 0
3 years ago
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