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goblinko [34]
1 year ago
7

Write the equation for the line that passes through the point (-6, 2)

Mathematics
1 answer:
Juli2301 [7.4K]1 year ago
4 0

The equation of the line that passes through the points (-6 , 2) and (-4 , -1) is 3x + 2y = -14 .

In the question ,

two points are given as  (-6 , 2) and (-4 , -1) .

we need to find the equation of the line passing through the given points .

to find the equation First we need to find the slope  ,

slope = (-1-2)/(-4-(-6))

slope = -3/(-4 + 6)

slope = -3/2

So , the equation of the line passing through the point (-6 , 2) with slope -3/2 is  

(y - 2) = (-3/2)(x - (-6))

y - 2 = (-3/2)(x + 6)

y - 2 = (-3/2)x - 9

y = (-3/2)x - 9 + 2

y = (-3/2)x - 7

2y = -3x - 14

3x + 2y = -14

Therefore , The equation of the line that passes through the points (-6 , 2) and (-4 , -1) is 3x + 2y = -14 .

The given question is incomplete , the complete question is

Write the equation for the line that passes through the point (-6, 2) and (-4,-1) , write the answer in fully reduced form .

Learn more about Equation Of Line here

brainly.com/question/21298390

#SPJ1

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4

Step-by-step explanation:

4 X 4 + 16

4 0
3 years ago
40% of Oatypop cereal boxes contain a prize. Hannah plans to keep buying cereal until she gets a prize. What is the probability
aleksley [76]

Answer:

(0.6)^{n}+n(0.4)(0.6)^{n-1}+\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}

Step-by-step explanation:

We will use the binomial distribution. Let X be the random variable representing the no. of boxes Hannah buys before betting a prize.

Our success is winning the prize, p =40/100 = 0.4

Then failure q = 1-0.4  = 0.6

Hannah keeps buying cereal boxes until she gets a prize. Then n be no. times she buys the boxes.

P(X ≤ 3) = P(X=0) +P(X=1)+P(X=2)+P(X=3)

             = \binom{n}{0}p^{0}q^{n-0} +  \binom{n}{1}p^{1}q^{n-1}+ \binom{n}{2}p^{2}q^{n-2}+ \binom{n}{3}p^{3}q^{n-3}


             =  q^{n}+npq^{n-1}+\frac{n(n-1)(p)^{2}q^{n-2}}{2}+\frac{n(n-1)(n-2)p^{3}q^{n-3}}{6}

             = (0.6)^{n}+n(0.4)(0.6)^{n-1}+[tex]\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}


7 0
3 years ago
Read 2 more answers
1. The difference of two numbers is 3, and the sum of three times the larger one and
vlada-n [284]

Answer: 25 and 22

Step-by-step explanation:

Since one number is 3 bigger than the other, we can call them x, and x-3.

Then we know that the sum of 3 times x and 2 times (x-3) is equal to 19, so we can make the equation

3x+2(x-3)=19

Simplifying would get you

3x+2x-6=19

adding the x's and adding six to both sides of the equations gets you

5x = 25

divide by 5 and

x=5

Put those numbers back into your previous labels for them, x and x-3, and you get 5 and 2

Hope this helps

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Step-by-step explanation:

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