The equation of the line that passes through the points (-6 , 2) and (-4 , -1) is 3x + 2y = -14 .
In the question ,
two points are given as (-6 , 2) and (-4 , -1) .
we need to find the equation of the line passing through the given points .
to find the equation First we need to find the slope ,
slope = (-1-2)/(-4-(-6))
slope = -3/(-4 + 6)
slope = -3/2
So , the equation of the line passing through the point (-6 , 2) with slope -3/2 is
(y - 2) = (-3/2)(x - (-6))
y - 2 = (-3/2)(x + 6)
y - 2 = (-3/2)x - 9
y = (-3/2)x - 9 + 2
y = (-3/2)x - 7
2y = -3x - 14
3x + 2y = -14
Therefore , The equation of the line that passes through the points (-6 , 2) and (-4 , -1) is 3x + 2y = -14 .
The given question is incomplete , the complete question is
Write the equation for the line that passes through the point (-6, 2) and (-4,-1) , write the answer in fully reduced form .
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