water vapor that has condensed and covers the ground in the morning
Answer:
The acceleration of the proton is 2.823 x 10¹⁷ m/s²
The acceleration of the electron is 5.175 x 10²⁰ m/s²
Explanation:
Given;
distance between the electron and proton, r = 7 x 10⁻¹⁰ m
mass of proton, = 1.67 x 10⁻²⁷ kg
mass of electron, = 9.11 x 10⁻³¹ kg
The attractive force between the two charges is given by Coulomb's law;
where;
k is Coulomb's constant = 9 x 10⁹ Nm²/c²
Acceleration of proton is given by;
F = ma
Acceleration of the electron is given by;
<span>G = gravitational constant
M = mass of the earth
R = radius of orbit of a satellite
r = radius of orbit of a second satellite
v = speed of the satellite
P = period of a satellite
p = period of a second satellite
Equate gravitational acceleration with centripetal acceleration
g = G*M/R^2 = v^2/R
Express the orbital speed in terms of the orbit circumference and period
v = 2*pi*R/P
And insert the expression for v into the first equation
G*M/R = 4*PI^2*R^2/P^2
G*M/R^3 = 4*pi^2/P^2
R^3/P^2 = 4*pi^2/(G*M) = constant = C
We can do the above since G and M are constants for all earth orbits
So we can write a second equation of the same form for another satellite and equate to get:
R^3/P^2 = r^3/p^2
r^3 = R^3*p^2/P^2
r = R*(p^2/P^2)^(1/3)
For the second satellite we have p = 8*P
r = R*(8^2)^(1/3) = R*(64)^(1/3) = 4*R</span>