Answer:
Therefore, the solutions of the quadratic equations are:

The graph is also attached.
Step-by-step explanation:
The solution of the graph could be obtained by finding the x-intercept.

Finding the x-intercept by substituting the value y = 0
so

∵ y = 0












So, when y = 0, then x values are 3, and 5.
Therefore, the solutions of the quadratic equations are:

The graph is also attached. As the graph is a Parabola. It is visible from the graph that the values of y = 0 at x = 5 and x = 3. As the graph is a Parabola.
Step-by-step explanation:
v= 4/3πr³
4/3×314/100×8×8×8
•
= 2,143.573
With cross multiplication you can find that they are the same. In both equations, x would be 100.
I think Sam is correct cuz SQ is a bigger rectangle and for OM it is smaller and we only know the width
The slope of points (-2,6) and (3,10) is m= 0.8