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leva [86]
2 years ago
11

What is the length of the hypotenuse? 12 5 X= Help

Mathematics
2 answers:
polet [3.4K]2 years ago
7 0

Answer:

13

Step-by-step explanation:

\sqrt{5^{2}   + 12^{2}} =  \sqrt{169}  \\  \\  \sqrt{169}  = 13

a²+b²=c²

Temka [501]2 years ago
3 0

Answer:

x = 13

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

5^2 + 12^2 = x^2

25+144 = x^2

169 = x^2

Taking the square root of each side

sqrt(169) = sqrt(x^2)

13 =x

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Flauer [41]

Answer:

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5 0
2 years ago
If m∠c=11x+85/3 and x=13 then what type of angle is c please help me with this
GuDViN [60]

Answer:

Acute angle

Step-by-step explanation:

Given that m<C = \frac{11x + 85}{3}, to find out the type of angle angle C is, evaluate the expression given by substituting x = 13, in the expression.

m<C = \frac{11x + 85}{3}

m<C = \frac{11(13) + 85}{3}

m<C = \frac{228}{3}

m<C = 76°

Acute angles are less than 90°.

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5 0
3 years ago
URGENT this is a question on my precalculus test I need help on. Thank you so much
sp2606 [1]

Answer:

a. 5i + 13j

b. 8i

c. 10i + 6j

Step-by-step explanation:

a. 2i + 6j + 3i + 7j = 5i + 13j

b. 3i + 7j + 5i - 7j = 8i

c. 2i + 6j + 3i + 7j + 5i - 7j = 10i + 6j

5 0
3 years ago
The age of some lecturers are 42,54,50,54,50,42,46,46,48 and 48 calculate the mean age and standard deviation
rjkz [21]

Answer:

Mean age: 48

Standard deviation: 4

Step-by-step explanation:

a) Mean

The formula for Mean = Sum of terms/ Number of terms

Number of terms

= 42 + 54 + 50 + 54 + 50 + 42 + 46 + 46 + 48+ 48/ 10

= 480/10

= 48

The mean age is 48

b) Standard deviation

The formula for Standard deviation =

√(x - Mean)²/n

Where n = number of terms

Standard deviation =

√[(42 - 48)² + (54 - 48)² + (50 - 48)² +(54 - 48)² + (50 - 48)² +(42 - 48)² + (46 - 48)² + (46 - 48)² + (48 - 48)² + (48 - 48)² / 10]

= √-6² + 6² + 2² + 6² + 2² + -6² + -2² + -2² + 0² + 0²/10

=√36 + 36 + 4 + 36 + 4 + 36 + 4 + 4 + 0 + 0/ 10

=√160/10

= √16

= 4

The standard deviation of the ages is 4

3 0
3 years ago
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