Ask question

Ask question

All categories

2 years ago

11

What is the length of the hypotenuse? 12 5 X= Help

2 answers:

polet [3.4K]2 years ago

7 0

Answer:

13

Step-by-step explanation:

$\sqrt{5^{2} + 12^{2}} = \sqrt{169} \\ \\ \sqrt{169} = 13$

a²+b²=c²

Temka [501]2 years ago

3 0

Answer:

x = 13

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

5^2 + 12^2 = x^2

25+144 = x^2

169 = x^2

Taking the square root of each side

sqrt(169) = sqrt(x^2)

13 =x

You might be interested in

PLEASE SHOW ALL THE STEPS THAT YOU USE TO SOLVE THIS PROBLEM

Mademuasel [1]

Answer:

{x = 1 , y=1, z=0

Step-by-step explanation:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

{-2 x - y + z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x - 3 y - 2 z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y+0 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y=1, z=0

6 0

3 years ago

OH NO!!! Madeleine’s data has been corrupted, again! Using the incomplete data file below, which she was able to recover from he

-Dominant- [34]

Answer:

a. N=25

b. X[bar]= 60.52

c. Y[bar]= 106.72

d. SSx= 115.24

e. ∑X*∑Y = 4036684

f. SSxy= 202020.3296

g. √(SSx*SSy)= 449.46

Step-by-step explanation:

Hello!

Using the attached data you need to calculate some statistics.

a) N

The sample size is listed under the first column "subject" You can see that 25 subjects qhere studied so N=25.

b.

The mean of set X is equal to X[bar]= ∑X/n= 1513/25= 60.52

∑X is listed in the second table.

c.

The mean of ser Y is Y[bar]= ∑Y/n= 2668/25= 106.72

∑Y is listed in the second table.

d.

Sum of Squares of set X SSx= ∑X²-[(∑X)²/n]= 91682-[(1513)²/25]= 115.24

e.

∑X*∑Y =1513*2668= 4036684

f.

SSxy= (∑X²-[(∑X)²/n]) * (∑Y²-[(∑Y)²/n])= (91682-[(1513)²/25]) * (286482*[(2668)²/25])= 202020.3296

g.

√(SSx*SSy)= √(115.24*1753)= 449.46

I hope you have a SUPER day!

3 0

3 years ago

43 ones x 3 ten equals

Svet_ta [14]

The answer is 1230!!!!!!!

4 0

3 years ago

Read 2 more answers

Help asap please!!<br> Find the measure of y.<br> A. 43<br> B. 53<br> C. 90<br> D. 47

Amiraneli [1.4K]

Answer:

$y=43$

Step-by-step explanation:

$y=2(90-46)/2$

$y=43$

<u>------------------------</u>

<u>OAmalOHopeO</u>

<u>-----------------------</u>

5 0

3 years ago

Solve for x give answer as radicals (roots)

skelet666 [1.2K]

Answer:

x = 15

Step-by-step explanation:

Use pythagorean theorem: $a^{2} +b^{2} = c^{2}$

$8^{2} +x^{2} =17^{2} \\ 64 + x^{2} = 289 \\\\x^{2} = 289 - 64\\x^{2} = 225\\x = 15$

8 0

3 years ago