9 fhwj bq bvq qvhj mbr ncvqa,a w m c qcfhq cm qc mqc cq w
Hey there!
For all this, we'll start with defining any variable as "a number", as we're using words.
a) Three less than the product of five and a number.
b) Two times the sum of x and y.
c) Three subtracted from the sum of a number and five.
Hopefully this helps!
I think to solve for this problem we need to subtract the given amounts.
19 - (-39) = 19 + 39 = 58
Given:
x = beginning number of newspapers
24 = sold in the morning
(x - 24) * 2/7 = sold in the afternoon
x * 1/2 = remaining newspapers
5/7 of the remaining newspaper is equal to 1/2 of the original number.
(x - 24) * 5/7 = 1/2 * x
5x/7 - 120/7 = x/2
5x/7 * 2/2 - 120/7 * 2/2 = x/2 * 7/7
10x/14 - 240/14 = 7x/14
10x/14 - 7x/14 = 240/14
3x/14 = 240/14
14 * 3x/14 = 14 * 240/14
3x = 240
x = 240/3
x = 80
80 - 24 = 56 remaining newspaper in the morning
56 * 2/7 = 16 sold in the afternoon
80 - 24 - 16 = 80/2
40 = 40 remaining newspaper for the day.
