Given:
The table represents a proportional relationship.
To find:
The equation of the function.
Solution:
If y is directly proportional to x, then

...(i)
where, k is the constant of proportionality.
From the given table it is clear that the function passes through (2,1). So, the equation must be satisfied by the point (2,1).
Putting x=2 and y=1 in (i), we get


Putting
, we get

Therefore, the correct option is A.
9514 1404 393
Answer:
(-3, 9), (-1, 11), (0, 12), (4, 16), (6, 18)
Step-by-step explanation:
The function definition tells you that adding 12 to the x-value will give you the value of f(x).
-3 +12 = 9, for example
The (x, f(x)) values for the table are shown above.
There are 4 vertices of a square to the right.
It should be bigger, think of a pie:
if you cut it into 2 parts, the pieces are big
if you cut it into 4 parts, the pieces are smaller
in both parts, the AMOUNT OF PIE stays the same, the size changes
here, we cut out 8 / 10 pieces, (manny)
ana has the same WHOLE amount, but in BIGGER pieces because she has an amount less than 8.
It works if you REDUCE THE FRACTION, 8/10 can be REDUCED to 4/5, Ana's pieces should be twice as big as Manny's, but she only has 4
They forget to say "not to scale". I'm guessing this is trig because I don't see another way to do it.
Let's consider x=chord PQ first. By the Law of Cosines

We have an isosceles triangle formed by two radii of 9 cm and x=PQ. By the Law of Cosines again,





The area of the circle is the fraction given by the angle,



Answer: 24.7 sq cm