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kolbaska11 [484]
3 years ago
9

Y=5x+11; domain = {-4, -1, 0}

Mathematics
1 answer:
weqwewe [10]3 years ago
6 0

Answer:

The domain is the set of x -coordinates, {0,1,2} , and the range is the set of y -coordinates, {7,8,9,10} . Note that the domain elements 1 and 2 are associated with more than one range elements, so this is not a function.

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Pleaseeee help its due today :( <br> thank you in advance &lt;3
Ksenya-84 [330]

Step-by-step explanation:

y = 1 / (cx + a) - b

At the x-axis intercept, y = 0.

=> 1 / (cx + a) - b = 0

=> 1 / (cx + a) = b

=> b(cx + a) = 1

=> bcx + ab = 1

=> bcx = 1 - ab

=> x = (1 - ab) / (bc)

Hence the answer is Option B.

8 0
3 years ago
Solve for x in 5x−19≤1 OR −4x+3&lt;−6
gogolik [260]

Answer:

I had x to be 4 or 9/4 that is my solution

7 0
3 years ago
Read 2 more answers
Find the value of x .just put the equation as the answer plz
Inessa [10]

Answer:

ok so the value of x is 147°.

the only angle we know is 42, we know a full rotation is 360° so we can deduct that 42° + 2x+1 + -124+x = 360.

minus 42 from both sides and solve for x,

we get 3x = 441; x = 147.

8 0
3 years ago
Please help me, im struggling
Molodets [167]

<u>Part 1</u>

<u />f(a)=4-7a+16a^2

<u>Part 2</u>

<u />f(a+h)=4-7(a+h)+16(a+h)^2\\\\=4-7(a+h)+16(a^2 +2ah+h^2)\\\\=4-7a-7h+16a^2 +32ah+16h^2

<u>Part 3</u>

<u />\frac{f(a+h)-f(a)}{h}=\frac{(4-7a-7h+16a^2 +32ah+16h^2-(4-7a+16a^2)}{h}\\\\=\frac{-7h+32ah+16h^2}{h}\\\\=32a+16h-7

7 0
2 years ago
Why does using FOIL on polynomial expressions match so closely to integer multiplication?
dezoksy [38]
<span> FOIL is a mnemonic rule for multiplying binomial (that is, two-term) algebraic expressions. </span>
<span>FOIL abbreviates the sequence "First, Outside, Inside, Last"; it's a way of remembering that the product is the sum of the products of those four combinations of terms. </span>

<span>For instance, if we multiply the two expressions </span>
<span>(x + 1) (x + 2) </span>
<span>then the result is the sum of these four products: </span>
<span>x times x (the First terms of each expression) </span>
<span>x times 2 (the Outside pair of terms) </span>
<span>1 times x (the Inside pair of terms) </span>
<span>1 times 2 (the Last terms of each expression) </span>
<span>and so </span>
<span>(x + 1) (x + 2) = x^2 + 2x + 1x + 2 = x^2 + 3x + 2 </span>
<span>[where the ^ is the usual way we indicate exponents here in Answers, because they're hard to represent in an online text environment]. </span>

<span>Now, compare this to multiplying a pair of two-digit integers: </span>
<span>37 × 43 </span>
<span>= (30 × 40) + (30 × 3) + (7 × 40) + (7 × 3) </span>
<span>= 1200 + 90 + 280 + 21 </span>
<span>= 1591 </span>

<span>The reason the two processes resemble each other is that multiplication is multiplication; the difference in the ways we represent the factors doesn't make it a fundamentally different operation. </span>
7 0
3 years ago
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