Answer:
a = 3
Step-by-step explanation:
1) Simplify 5a - 9 + a to 6a - 9.

2) Add 9 to both sides.

3) Simplify 9 + 9 to 18.

4) Divide both sides by 6.

5) Simplify 18/6 to 3.

Therefor, the answer is, a = 3.
If there is such a scalar function <em>f</em>, then



Integrate both sides of the first equation with respect to <em>x</em> :

Differentiate both sides with respect to <em>y</em> :


Integrate both sides with respect to <em>y</em> :

Plug this into the equation above with <em>f</em> , then differentiate both sides with respect to <em>z</em> :



Integrate both sides with respect to <em>z</em> :

So we end up with

Answer:
Slope-int form: y = 3x+5
Standard form: y - 3x = 5.
Step-by-step explanation:
(reminder: slope-intercept form is expressed as y=mx+b, and standard form is expressed as ax+bx=c.)
Since the slope is 3, the coefficient of x is also 3, which makes the equation y=3x.
But the y coordinate of the equation at x = -2 is -6, so we need to add 5 to the end of the equation, leaving you with:
y=3x+5.
To convert it to standard form, subtract 3x from both sides:
y - 3x = 5.
I hope this helped you.
Answer:

Step-by-step explanation:



The domain of the function is \[A \ge0\] If A is negative we get an imaginary number for the radius. This makes sense because the area of a circle cannot be negative.