Question

Write parametric equations of the line -3x+4y=7

Answer 1

Answer:

x=t, y=(3/4)t+(7/4)

Step-by-step explanation:

We start by changing the equation the slope-intercept form.

4y=3x+7

y=(3/4)x+(7/4)

then we set x equal to t

x=t

and substitute

y=(3/4)t+(7/4)

that's it.

Answer 2

Answer:

x = 1 + t and y = 2.5 + 0.75t

Step-by-step explanation:

Parametric equations are the equations in which the all the variables of the equation are written in terms of a single variable. For example in 2-D plane, the equation of the line is given by y=mx+c, there x is the independent variable, y is the dependent variable, m is the slope, and c is the y-intercept. The equation of the given line is -3x + 4y = 7. The goal is to convert the variables x and y in terms of a single variable t. First of all, take two points which lie on the line. By taking x=1, y comes out to be 2.5 and by taking x=0, y comes out to be 2.5. The general form of the straight line is given by:

(x, y) = (x0, y0) + t(x1-x0, y1-y0), where (x, y) is the general point, (x0, y0) is the fixed point, t is the parametric variable, and (x1-x0, y1-y0) is the slope.

Let (x0, y0) = (1, 2.5) and (x1, y1) = (0, 1.75). Substituting in the general equation gives:

(x, y) = (1, 2.5) + t(1, 0.75). This implies that x = 1 + t and y = 2.5 + 0.75t!!!