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2 years ago

Multiply using distributive property. (2m-5)(3m+8) PLEASE HELP!!! ASAP!!!

Mathematics

2 answers:

Ivanshal [37]2 years ago

8 0

Answer:

6m^2 + m - 40.

Step-by-step explanation:

(2m - 5)(3m + 8)

= (2m * 3m) + (-5 * 3m) + (2m * 8) + (-5 * 8)

= 6m^2 - 15m + 16m - 40

= 6m^2 + m - 40.

Hope this helps!

Lorico [155]2 years ago

3 0

Answer: 6m^2 +m -40

Step-by-step explanation: Distributing binomials calls for the FOIL method.

Multiply the First times the First: 3m×2m= 6m^2. (^2 means squared when we can't use superscript for exponents.)

Then multiply and combine the Outside and Inside terms: 2m ×8=16m. and -5 ×3m= -15m

16m - 15m = m

Then multiply the Last terms: -5×8= -40

You end up with

6m^2 + m -40

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3 years ago

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Arlecino [84]

Let's say the numbers are "a" and "b"
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so "b" is "4 more than 5 times" "a"

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so.. whatever "a" is, "b" is 5a+4

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so $\bf \begin{cases}
a+b=22\\
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2 years ago

Which expression is equivalent to ^5 square root 13^3

joja [24]

Answer:

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Step-by-step explanation:

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2 years ago

Help me with this❤️ please

PtichkaEL [24]

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2 years ago

A recent article in The Wall Street Journal compared the cost of adopting children from China with that of Russia. For a sample

denpristay [2]

Answer:

We can conclude the mean cost is larger for adopting children from Russia.

Step-by-step explanation:

To answer this question we can perform an hypothesis testing on the differences of the means with the following null and alternative hypothesis:

$H_0: \mu_1\leq\mu_2\\\\H_1: \mu_1>\mu_2$

The significance level we assume is 0.05.

First we calculate the mean standard error:

$MSE=\frac{SSE}{df}=\frac{n_1\sigma_1^2+n_2\sigma_2^2}{(n_1-1)+(n_2-1)} =\frac{16*835^2+18*1545^2}{16-1+18-1} =1,691,314$

The harmonic mean of the sample sizes is:

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{0.0625+0.0556}=\frac{2}{0.1181}=16.94$

Then we can calculate the estimated standard deviation as:

$\sigma=\sqrt{\frac{2MSE}{n_h} } =\sqrt{\frac{2*1691314}{16.94} } =447$

The t-statistic can be calculated as:

$t=\frac{\Delta M-\Delta \mu}{\sigma}=\frac{(11045-12840)-0}{447} =\frac{-1795}{447}= -4.015$

The degrees of freedom are $df=n_1+n_2-2=18+16-2=32$ .

We can look up the P-value in a table or applet. For t=-4.015 and df=32, the P-value is 0.00017.

The P-value is smaller than the significance level, so the effect is significant and the null hyphotesis (China cost is equal or less than in Russia) is rejected.

We can conclude the mean cost is larger for adopting children from Russia.

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2 years ago