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Scorpion4ik [409]
3 years ago
8

Grace has a coupon for $2 off the regular price off the regular price of each pair of jeans she buys she buys 4 pairs of jeans w

ith a regular price of $23 each
write and evaluate an expressions to find the total cost of the jeans
Mathematics
2 answers:
m_a_m_a [10]3 years ago
7 0
It would me 23-4=19x3=$76
zhenek [66]3 years ago
5 0

Answer:

Total cost of the jeans is:

$76

Step-by-step explanation:

grace has a coupon for $2 off the regular price of each pair of jeans she buys.

She buys 4 pairs of jeans with a regular price of $23 each.

i.e. she buys each pair of jeans for $(23-4)

i.e. she buys each pair of jeans for $19

Cost of 1 pair of jeans=$19

Cost of n pair of jeans= $19n

i.e. We have to evaluate the expression 19n to find the cost of n pair of jeans

Cost of 4 pair of jeans= $(19×4)

                                    = $76

Hence, Total cost of the jeans is:

$76

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Four times a first number decreased by a second number is - 14. The first
mel-nik [20]

Answer:

f = -5, s = -6

Step-by-step explanation:

F= first number

S= second number

4f - s = -14

f + 3s = -23

3(4f - s = -14)

12f - 3s = -42

+ f + 3s = -23

13f = -65

————

13

f = -5

4f - s = -14

4(-5) - s = -14

-20 - s = -14

+20 +20

-s = 6

———

-1

s = -6

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3 years ago
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{{{ THE BOLDED CHARACTERS SHOULD BE SMALL. }}}

SEQUENCE: 6, 18, 54, 162

18/6 = 3

54/18 = 3

162/54 = 3

then, r (common ratio) = 3

_________________________________________

RECURSIVE RULE: r = 3

an = a(n - 1) × r       [formula]

ANSWER: an = a(n - 1) × 3

_________________________________________

ITERIATIVE RULE: r = 3, a1 = 6

an = a1 × r^(n - 1)       [formula] [ ^(n-1) is an exponent]

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Step-by-step explanation:

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iris [78.8K]

Solution:

we are given that

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we have been asked to find the probability that a number less than 2 will occur on one toss of the number cube.

Since a number less than 2 is only one and that is "1" and total number of possible outcome is 6.

and as we know that probability is given using the formula

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Substitute the values we get

P(E)= \frac{1}{6}

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IRISSAK [1]
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