V = (1/3) π r² t
= (1/3) π (10 cm)². 16 cm
= (1/3) π (100 cm²). 16 cm
= (1/3) π (1600 cm³)
= (1600π)÷3 cm³ (B)
Answer:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:(30/19,2/19)
Equation Form: x=30/19, y=2/19
Let's multiply each of the four squares, one by one.
In blue, we see the dimensions are x by x. x times x = x^2
In pink, we see the dimensions are 9 by x. x times 9 = 9x
In green, the dimensions are x by 3. 3 times x = 3x
And finally, yellow's dimensions are 3 by 9. 3 times 9 = 27
We can now just add all these areas to find the total area:
x^2 + 12x + 27
Step One
Find the sum of the fractions for Monday and Tuesday
1/2 + 2/5
The common denominator for these 2 days is 10
1/2: 1*5/(2*5) = 5/10
2/5:2*2/(2*5) = 4/10
Add these two equivalent fractions together.
5/10 + 4/10 = 9/10
The first 2 days resulted in 9/10 of the shed being completed.
Step Two
Find out how much (in terms of fractions) is left of the shed.
Let the whole shed = 1
Let what has been done = 9/10
What remains is 1 - 9/10 = 1/10
Answer: 1/10 of the shed needs to be done
