3 years ago

A)y

Mathematics

1 answer:

prohojiy [21]3 years ago

8 0

The answer would be B, due to the fact that the shaded area is above the line.

You might be interested in

If someone could help me that would be amazing! Thank you!

Anastasy [175]

I’d say 135 or B! I hope this helps!

4 0

3 years ago

Find the sum of the first 10 terms of the following geometric sequences:<br> {3, 6, 12, 24, 48...)

bonufazy [111]

Answer:

3069

Step-by-step explanation:

q=6/3=2

s10=3(2^10-1)÷(2-1)=3×(1024-1)=

3069

because sn=a1(q^n-1)/(q-1)

3 0

3 years ago

Math help soon please

mixas84 [53]

The slope is 3/5 just count the units up and to the side

5 0

3 years ago

At Glencliff High School, the photography

olga_2 [115]

Answer:

23+12=

Step-by-step explanation:

you just need figure it out in your head and see what sounds right

4 0

3 years ago

Read 2 more answers

Find the Y-coordinate of point P that lies 1/3 along segment RS, where R (-7, -2) and S (2, 4).

QveST [7]

Solution:

Given that the point P lies 1/3 along the segment RS as shown below:

To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have

$\begin{gathered} RP:PS \\ \Rightarrow\frac{1}{3}:\frac{2}{3} \\ thus,\text{ we have} \\ 1:2 \end{gathered}$

Using the section formula expressed as

$[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]$

In this case,

$\begin{gathered} m=1 \\ n=2 \end{gathered}$

where

$\begin{gathered} x_1=-7 \\ y_1=-2 \\ x_2=2 \\ y_2=4 \end{gathered}$

Thus, by substitution, we have

$\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}$

Hence, the y-coordinate of the point P is

$0$

8 0

1 year ago