Answer:
<h2>C.) y <u><</u><u> </u><u>1</u><u> </u><u> </u></h2><h2><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>---<u> </u><u> </u>× + 2</h2><h2><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>3</h2>
Step-by-step explanation:
your answer is this
Well this is easy.
We have linear inequality,
Simplifying this a bit to get,
Divide by 3 (both sides),
Or with interval notation, 
.
Hope this helps. :)
13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed
<u>Step-by-step explanation:</u>
Total mass of acid required= 85 ounces
Let the mass of 72% acid be 'a'
Let the mass of 25% acid be 'b'
a + b = 85
b = 85-a
85(40/100) = a(72/100) + b(25/100)
85(2/5) = a(72/100) +(85- a) (25/100)
34 = (72a/100) + (2125/100) - (25a/100)
34 - (2125/100) = (72a + 25a) /100
(3400-2125)/100 = 97a /100
97a = 1275
a = 13.15 ounces
b = 85 - 13.14
b = 71.85 ounces
13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed
Yes they are equal they both have a side that is 25 degrees
Answer
103.333333333
Explanation
Since 12oz of ale contains 124 calories, you have to divide 124 by 12 to find how many calories are in 1 oz of ale. then you multiply 10.33 by 10 to find how many calories are in a 10oz glass of ale.
