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maw [93]
3 years ago
6

A bit in a hurry here! Could anyone please help out here?

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0

k = .6

32^.6 x 10 = 80

32^.6 = 8

8 x 10 = 80

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\sf\huge\underline{\star Solution:-}

\rightarrowLet the women's height be AE and distance between the women and tower be AC.

Also let the height of tower be BC.

\rightarrowNow, clearly it is forming a triangle.

So, in triangle ABC,

\rightarrow\sf{Tan50° \:= \: \frac{BC}{AC}}

\rightarrow\sf{1.19 \:= \: \frac{BC}{50}}

\rightarrow\sf{1.19 ×50\:= \: BC}

\rightarrow\sf{59.5m\:= \: BC}

\rightarrowHence, BC = 59.5m

So, BD(total height of the tower)\sf{ = \:BC+CD}

\sf{= \:59.5+1.65}

\sf{=\: 61.15m}

Therefore, total height of the tower =\sf\purple{ 61.15m.}

________________________________

Hope it helps you:)

5 0
2 years ago
Read 2 more answers
Check screenshot. that is where the question is placed.
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C is the awnser I believe correct me if I’m wrong
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