I need help its math

there are 200 end of the year school dance tickets students who have perfect attendance are able to presage them in advance if 1

Umnica [9.8K]

$200 - 18 = 182$
182 is the answers

3 0

2 years ago

The battery standby duration (in hours) of a new model of cell phone is known to be normally distributed. Ten pieces of such new

Stells [14]

x = number of hours

want to find probability (P) x >= 13

x is N(14,1) transform to N(0,1) using z = (x - mean) / standard deviation so can look up probability using standard normal probability table.

P(x >= 13) = P( z > (13 - 14)/1) = P(z > -1) = 1 - P(z < -1) = 1 - 0.1587 = 0.8413

To convert that to percentage, multiply 100, to get 84.13%

3 0

2 years ago

Emil is running a lemonade stand. He sells half of his lemonade in the morning, a quarter of what was left at lunchtime, and a t

masya89 [10]

Emil starts the day with 16 liters of lemonade if he is left with 4 liters by the end of the day. Computed using the fractional values given.

Let the initial quantity of lemonade with Emil be x liters.

Quantity sold by Emil in the morning = Half of his lemonade = (1/2)x liters, that is half fraction of x.

Quantity left with Emil = x - x/2 = x/2 liters, that is half fraction of x.

Quantity sold by Emil at lunchtime = Quarter of what was left = (1/4)(x/2) liters = x/8 liters, that is the one-eight fraction of x.

Quantity left with Emil = x/2 - x/8 = 3x/8 liters, that is the three-eight fraction of x.

Quantity sold by Emil in the afternoon = One-third of what was left = (1/3)(3x/8) liters = x/8 liters, that is the one-eight fraction of x.

Quantity left with Emil = 3x/8 - x/8 = x/4 liters, that is the quarter fraction of x.

Now, we are said that Emil closes for the day with 4 liters remaining.

Therefore, x/4 = 4, or, x = 4*4 = 16 liters.

Therefore, Emil started the day with 16 liters of lemonade.

Learn more about fractions at

brainly.com/question/11562149

#SPJ10

6 0

1 year ago

Three girls cut out decimal models of hundredths. Amber doesn't shade any of her models. Grace qualifies three fifths of a model

Varvara68 [4.7K]

Answer:

$Amber = 0$

$Grace = 0.60$

$Marsha =1.70$

Step-by-step explanation:

Given

Decimal Grid = Hundredths

$Amber = None$

$Grace = \frac{3}{5}th$

$Marsha = 1 + \frac{7}{10}th$

To solve for each:

We have:

For Amber:

$Amber = 0 * 100$

$Amber = 0$

For Grace:

$Grace = \frac{3}{5}th$

$Grace = \frac{3}{5} * 100$

$Grace = \frac{300}{5}$

$Grace = 60$

This means that Grace shaded 60 of the hundredth models.

Decimal shaded is:

$Grace = 60 * \frac{1}{100}$

$Grace =\frac{60}{100}$

$Grace = 0.60$

For Marsha:

$Marsha = 1 + \frac{7}{10}th$

$Marsha = \frac{10 + 7}{10}th$

$Marsha = \frac{17}{10}th$

$Marsha = 1.7th$

Multiply this by 100, to get the number of shaded

$Marsha = 1.7 * 100$

$Marsha = 170$

This means that Marsha shaded 170 of the hundredth models.

Decimal shaded is:

$Marsha = \frac{170}{100}$

$Marsha =1.70$

5 0

2 years ago

-8 ( y + 4 ) = 10y + 4

maks197457 [2]

Let's solve your equation step-by-step.−8(y+4)=10y+4

Step 1: Simplify both sides of the equation.−8(y+4)=10y+4

Simplify: (−8)(y)+(−8)(4)=10y+4(Distribute)−8y+−32=10y+4−8y−32=10y+4

Step 2: Subtract 10y from both sides.−8y−32−10y=10y+4−10y−18y−32=4

Step 3: Add 32 to both sides.−18y−32+32=4+32−18y=36

Step 4: Divide both sides by -18.−18y−18=36−18y=−2

Answer:y=−2

Good luck mate :P

7 0

2 years ago

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