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Nataly_w [17]
2 years ago
15

The area of the triangle is 33.6 square inches. If the h eyesight of the triangle is 4 inches what is the length of the base

Mathematics
1 answer:
DerKrebs [107]2 years ago
5 0
Using the formula for the area of a triangle we can solve for the base.

The formula for area of a triangle is : Area = 1/2 x base x height

We are given the area and the height:

33.6 = 1/2 x 4 x base

Multiply both sides by 2 to remove the 1/2:

67.2 = 4 x base

Divide both sides by 4 to solve for the base:

67.2 /4 = 16.8
 
Check: Area = 1/2 x 4 x 16.8 = 33.6

The base is 16.8 inches.

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Answer:

4/10, 6/15, 8/20, and 10/25

Step-by-step explanation:

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You buy a house for $130000. it appreciates 6% per year. how much is it worth in 10 years
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Growth because “appreciate” 6% per year

Initial amount = 130000
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2 years ago
to win a basketball game, one team scored 151 points. They made a total of 62 two-pointers and three pointers how many of the ba
wolverine [178]

That's a huge number of points.

First: Calculate the value of 62 two pointers

62 * 2 = 124

Second: find the number of points that were due to 3 pointers.

151 - 124 = 27

Third: Divide by 3 to find the number of 3 pointers.

27÷3 = 9

Answer: There were 9 three pointers.

3 0
3 years ago
A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t
MakcuM [25]

Answer:

165.

Step-by-step explanation:

Since repetition isn't allowed, there would be 11 choices for the first donut, (11 - 1) = 10 choices for the second donut, and (11 - 2) = 9 choices for the third donut. If the order in which donuts are placed in the bag matters, there would be 11 \times 10 \times 9 unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type 3 \times 2 \times 1 = 6 times.

For example, if a bag includes donut of type x, y, and z, the count 11 \times 10 \times 9 would include the following 3 \times 2 \times 1 arrangements:

  • xyz.
  • xzy.
  • yxz.
  • yzx.
  • zxy.
  • zyx.

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count 11 \times 10 \times 9 by 3 \times 2 \times 1 = 6 to find the actual number of donut combinations:

\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of 3 objects from a set of 11 distinct objects:

\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

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