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padilas [110]
3 years ago
12

True or False? The incenter of a triangle is the center of the only circle that can be circumscribed about it.

Mathematics
2 answers:
Debora [2.8K]3 years ago
7 0
The answer would be False
MaRussiya [10]3 years ago
4 0

Answer:false


Step-by-step explanation: apex


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-2/3c-9/5+14c+3/10 please help so confused!
natita [175]

Answer:1 4

Step-by-step explanation:

3 0
3 years ago
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The speed of light is 3 x 10 8 meters per second (m/s). What is the speed of light in miles per year (mi/yr)
GenaCL600 [577]

Answer:

the  speed of light in miles per year is 5.88 × 10^12 mi / year

Step-by-step explanation:

The computation of the speed of light in miles per year is shown below;

As we know that

1 m/sec = 1 ÷ 1609  mi/sec

3 ×10^8 m/sec = (3 × 10^8) ÷ (1609)

= (3 × 10^8 × 60 × 60 × 24 × 365) ÷ (1609)

= 5.88 × 10^12 mi / year

Hence, the  speed of light in miles per year is 5.88 × 10^12 mi / year

8 0
3 years ago
Can someone help me with this one ​
yKpoI14uk [10]

Answer:

it seems as if there are no numbers . try putting something in there.

Step-by-step explanation:

6 0
3 years ago
Convert 5.6 m into centimeters.<br> Show work.
Nata [24]

Answer:

560 cm

Step-by-step explanation:

Step 1: Find conversion

1 m = 100 cm

Step 2: Convert

5.6 m · 100 cm/m = 560 cm

6 0
4 years ago
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Find the sum of the first five terms using the geometric series formula for the sequence left curly bracket 1 half comma space m
MatroZZZ [7]

Answer:

\bold{\dfrac{11}{2 }}

Step-by-step explanation:

Given the geometric series:

\{\dfrac{1}2, -1, 2, -4,  ..... \}

To find:

Sum of series upto 5 terms using the geometric series formula = ?

Solution:

Formula for sum of a n terms of a geometric series is given as:

S_n=\dfrac{a(1-r^n)}{1-r} \ \{r

a is the first term of the geometric series

r is the common ratio between each term (2nd term divided by 1st term or 3rd term divided by 2nd term ..... ).

Here:

a = \dfrac{1}{2}

r = \dfrac{-1}{\dfrac{1}{2}} = -2

n=5

So, applying the formula for given values:

S_5=\dfrac{\dfrac{1}2(1-(-2)^5)}{1-(-2)} \\\Rightarrow S_5=\dfrac{1-(-32)}{2 \times 3} \\\Rightarrow S_5=\dfrac{1+32}{6} \\\Rightarrow S_5=\dfrac{33}{6} \\\Rightarrow \bold{S_5=\dfrac{11}{2}}

So, the answer is

\bold{\dfrac{11}{2 }}

3 0
4 years ago
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