<span>Thomas rented 2 bicycles, which were late for return by 6 days. His fine for being late was 18$. If the fine for being late is count by multiplying the number of bicycles with the duration of the late, the answer would be:
fine = number of bicycle * duration of late
$18 =fine rate* 2 bicyles * 6 days
fine rate= (($18/ 2 bicyles) / 6 days) = $0.66 /bicycle days</span>
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Evaluate the indefinite integral:

Make a trigonometric substitution:

so the integral (i) becomes


Now, substitute back for t = arcsin(x²), and you finally get the result:

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You could also make
x² = cos t
and you would get this expression for the integral:

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which is fine, because those two functions have the same derivative, as the difference between them is a constant:
![\mathsf{\dfrac{1}{2}\,arcsin(x^2)-\left(-\dfrac{1}{2}\,arccos(x^2)\right)}\\\\\\ =\mathsf{\dfrac{1}{2}\,arcsin(x^2)+\dfrac{1}{2}\,arccos(x^2)}\\\\\\ =\mathsf{\dfrac{1}{2}\cdot \left[\,arcsin(x^2)+arccos(x^2)\right]}\\\\\\ =\mathsf{\dfrac{1}{2}\cdot \dfrac{\pi}{2}}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cdfrac%7B1%7D%7B2%7D%5C%2Carcsin%28x%5E2%29-%5Cleft%28-%5Cdfrac%7B1%7D%7B2%7D%5C%2Carccos%28x%5E2%29%5Cright%29%7D%5C%5C%5C%5C%5C%5C%0A%3D%5Cmathsf%7B%5Cdfrac%7B1%7D%7B2%7D%5C%2Carcsin%28x%5E2%29%2B%5Cdfrac%7B1%7D%7B2%7D%5C%2Carccos%28x%5E2%29%7D%5C%5C%5C%5C%5C%5C%0A%3D%5Cmathsf%7B%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%20%5Cleft%5B%5C%2Carcsin%28x%5E2%29%2Barccos%28x%5E2%29%5Cright%5D%7D%5C%5C%5C%5C%5C%5C%0A%3D%5Cmathsf%7B%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%20%5Cdfrac%7B%5Cpi%7D%7B2%7D%7D)

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and that constant does not interfer in the differentiation process, because the derivative of a constant is zero.
I hope this helps. =)
Answer is 12
K=y/x (rise over run)
The same rise over run happens to the next point, up 12 over 1
28/80 and then you simplify it by dividing the numerator and denominator by 4 and you get 7/20.
B. 7/20 is the correct answer
Answer:
Its 0, 1.
Step-by-step explanation:
ItsQuipo on yt