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fomenos
3 years ago
5

You mix soda water, fruit punch concentrate, and ginger ale in the ratio of 1 : 2 : 5 to make fruit punch. How many pints of eac

h ingredient should you use to make 4 gallons of fruit punch?
Mathematics
1 answer:
SIZIF [17.4K]3 years ago
3 0
All you do is 1x+2x+5x=8x then you turn 4 s into pints. 1 gallon equals 4 pints 4*4=16 pints. 8x=16 x=2. Then you multiply everything by 2

1*2=2 
2*2=4
2*5=10

2pints of soda water
4 pints of fruit punch
10 pints of ginger ale
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Create an equation to show how to solve this problem: Thomas rented 2 bicycles, which were late for return by 6 days. His fine f
Zinaida [17]
<span>Thomas rented 2 bicycles, which were late for return by 6 days. His fine for being late was 18$. If the fine for being late is count by multiplying the number of bicycles with the duration of the late, the answer would be:

fine = number of bicycle * duration of late
$18 =fine rate* 2 bicyles * 6 days
fine rate= (($18/ 2 bicyles) / 6 days) = $0.66 /bicycle days</span>
6 0
3 years ago
Find \(\int \dfrac{x}{\sqrt{1-x^4}}\) Please, help
ki77a [65]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2867785

_______________


Evaluate the indefinite integral:

\mathsf{\displaystyle\int\! \frac{x}{\sqrt{1-x^4}}\,dx}\\\\\\ \mathsf{=\displaystyle\int\! \frac{1}{2}\cdot 2\cdot \frac{1}{\sqrt{1-(x^2)^2}}\,dx}\\\\\\ \mathsf{=\displaystyle \frac{1}{2}\int\! \frac{1}{\sqrt{1-(x^2)^2}}\cdot 2x\,dx\qquad\quad(i)}


Make a trigonometric substitution:

\begin{array}{lcl}&#10;\mathsf{x^2=sin\,t}&\quad\Rightarrow\quad&\mathsf{2x\,dx=cos\,t\,dt}\\\\&#10;&&\mathsf{t=arcsin(x^2)\,,\qquad 0\ \textless \ x\ \textless \ \frac{\pi}{2}}\end{array}


so the integral (i) becomes

\mathsf{=\displaystyle\frac{1}{2}\int\!\frac{1}{\sqrt{1-sin^2\,t}}\cdot cos\,t\,dt\qquad\quad (but~1-sin^2\,t=cos^2\,t)}\\\\\\&#10;\mathsf{=\displaystyle\frac{1}{2}\int\!\frac{1}{\sqrt{cos^2\,t}}\cdot cos\,t\,dt}

\mathsf{=\displaystyle\frac{1}{2}\int\!\frac{1}{cos\,t}\cdot cos\,t\,dt}\\\\\\&#10;\mathsf{=\displaystyle\frac{1}{2}\int\!\f dt}\\\\\\&#10;\mathsf{=\displaystyle\frac{1}{2}\,t+C}


Now, substitute back for t = arcsin(x²), and you finally get the result:

\mathsf{\displaystyle\int\! \frac{x}{\sqrt{1-(x^2)^2}}\,dx=\frac{1}{2}\,arcsin(x^2)+C}          ✔

________


You could also make

x² = cos t

and you would get this expression for the integral:

\mathsf{\displaystyle\int\! \frac{x}{\sqrt{1-(x^2)^2}}\,dx=-\,\frac{1}{2}\,arccos(x^2)+C_2}          ✔


which is fine, because those two functions have the same derivative, as the difference between them is a constant:

\mathsf{\dfrac{1}{2}\,arcsin(x^2)-\left(-\dfrac{1}{2}\,arccos(x^2)\right)}\\\\\\&#10;=\mathsf{\dfrac{1}{2}\,arcsin(x^2)+\dfrac{1}{2}\,arccos(x^2)}\\\\\\&#10;=\mathsf{\dfrac{1}{2}\cdot \left[\,arcsin(x^2)+arccos(x^2)\right]}\\\\\\&#10;=\mathsf{\dfrac{1}{2}\cdot \dfrac{\pi}{2}}

\mathsf{=\dfrac{\pi}{4}}         ✔


and that constant does not interfer in the differentiation process, because the derivative of a constant is zero.


I hope this helps. =)

6 0
3 years ago
Do anyoneeeeeee know this??????????????????????????????????????
Dennis_Churaev [7]

Answer is 12

K=y/x (rise over run)

The same rise over run happens to the next point, up 12 over 1

5 0
2 years ago
Read 2 more answers
Please help!! 55 points!!
Sedbober [7]
28/80 and then you simplify it by dividing the numerator and denominator by 4 and you get 7/20.

B. 7/20 is the correct answer
5 0
3 years ago
Middle School Math Medium Level
Nata [24]

Answer:

Its 0, 1.

Step-by-step explanation:

ItsQuipo on yt

7 0
2 years ago
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