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3 years ago

6

ernesto and his family went to dinner, the tax is 6% of the price of the meal. ernesto leaves an 18% tip. with tax and tip the t

otal cost is $72.39. write an equation that models this situation.

1 answer:

Pie3 years ago

5 0

The equation would be something like this:
y=72.39+ .18x+.06x
then simplify
y=72.39+.24x

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Matrix A has 2 rows and 3 columns whereas matrix B has3 rows and 2 column

sergeinik [125]

Step-by-step explanation:

for any matrix multiplication number of columns of first matrix should be equal to number of rows of second matrix.

For AB

A has 3 columns and B has 3 rows so it matches . Hence can be multiplied.

For BA

B has 2 columns and A has 2 rows it also matches so can be multiplied

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2 years ago

Jeanine was making a baking. She used 1/2 cup of flour to make cookies and 2/3 cup of flour to make brownies. How much flour did

Fudgin [204]

Answer:

1 and 1/6 cups of flour

Step-by-step explanation:

We need the fractions to have common denominators so multiply 1/2 by 3 and 2/3 by 2 to get the common denominator of 6.

1/2 x 3/3 = 3/6

2/3 x 2/2 = 4/6

Add the two fractions

3/6 + 4/6 = 7/6 or 1 & 1/6

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3 years ago

Use f(x) = 1/2 x and f -1(x) = 2x to solve the problems. f(2) = 1 f−1(1) = 2 f−1(f(2)) = 2 f−1(−2) = f(−4) = f(f−1(−2)) =

vampirchik [111]

Answer:

In this problem, we are given the following functions:

$f(x)=\frac{1}{2}x$

and its inverse function:

$f^{-1}(x)=2x$

First of all, we want to calculate $f(2)$ . This can be obtained by substituting

x = 2

into f(x). Doing so, we find:

$f(2)=\frac{1}{2}\cdot 2 = 1$

Then we want to calculate $f^{-1}(1)$ . We can do it by substituting

x = 1

into $f^{-1}(x)$ . Doing so,

$f^{-1}(1)=2\cdot 1 = 2$

Then we want to calculate $f^{-1}(f(2))$ , which can be found by calculating f(2) and then using it as input for $f^{-1}(x).$ We know that

f(2) = 1

Therefore,

$f^{-1}(f(2))=f^{-1}(1)=2$

Then we want to calculate $f^{-1}(-2)$ , which can be calculated by plugging

x = -2

into $f^{-1}(x)$ . Doing so,

$f^{-1}(-2)=2\cdot (-2)=-4$

Then we want to calculate $f(-4)$ ; by substituting

x = 4

into f(x), we find

$f(-4)=\frac{1}{2}\cdot (-4)=-2$

Finally, we want to find $f(f^{-1}(-2))$

We know already that

$f^{-1}(-2)=-4$

So we have:

$f(f^{-1}(-2))=f(-4)=-2$

7 0

3 years ago

Read 2 more answers

A 5 inch bamboo shoot doubles in height every 3 days. if the equation y=ab^x , where x is the number of doubling periods, repres

Eddi Din [679]

Answer = a = 5 b = 3

6 0

3 years ago

A math test is worth 100 points and has 38 problems. Each problem is worth either 5 points or 2 points. How many problems of eac

Nat2105 [25]

Answer:

<em><u>5</u></em><em><u> </u></em><em><u>points</u></em><em><u> </u></em><em><u>question</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>8</u></em>

<em><u>and</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>po</u></em><em><u>ints</u></em><em><u> questions</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em>

Step-by-step explanation:

Let the number of 5 points questions be x and number of the 2 points questions be y !!

Given :- The paper has 38 problems

i.e,

number of 5 points Q + number of 2point Q = 38

=> x + y = 38

=> x = 38 - y .... ( i )

And , The test worth 100 pts :-

There must be x number of Questions which carry 5 points and there must y number of questions which carries 2 points ( as assume above )

so, 5x + 2y = 100 .... ( ii )

Putting value of the x in ( ii )

5 ( 38 - y ) + 2y = 100

190 - 5y + 2y = 100

- 3y = - 90

y = 30

Putting value of y in ( i )

x = 38 - y

x = 38 - 30

x = 8

So, the Number of 5points Question is

x = 8

and , the number of 2 points questions is y = 30 !!

4 0

3 years ago