How many 5-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed?
valentinak56 [21]
50 different 5-digit numbers because it would be 5x10 which equals 50.
Answer: no real solution
Thus, the function has no x- intercept
Step-by-step explanation:
Answer:
Q1) ans-16%
Q2) ans-50%
Q3) ans- 16%
Q4) yes, I think the question 3 and 1 are same
Answer:
r = 2
Step-by-step explanation:
(2-3)/(6-5)
= -1/1
= -1