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3 years ago

Which statement is false

Mathematics

1 answer:

Feliz [49]3 years ago

4 0

Answer:

Step-by-step explanation:

So this statement is false. Example 4: Every integer is a rational number. This is true because every integer can be written as a fraction with a denominator of 1. Example 5: Every natural number is a whole number, integer, and a rational number.

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Whats the the answer<br> for the money chapter test on time4learning

Rom4ik [11]

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5 0

3 years ago

Read 2 more answers

What is the missing expression that would make the left-hand-side of the equation equal to the right-hand-side?

o-na [289]

Given:

The equation is

$\dfrac{???}{x-2}/\dfrac{x^2-1}{x^2-4x+4}=\dfrac{5(x-2)}{x-1}$

To find:

The missing value.

Solution:

Let the missing value be k.

$\dfrac{k}{x-2}/\dfrac{x^2-1}{x^2-4x+4}=\dfrac{5(x-2)}{x-1}$

$\dfrac{k}{x-2}\times \dfrac{x^2-2(x)(2)+2^2}{x^2-1^2}=\dfrac{5(x-2)}{x-1}$

Using the formulae $(a-b)^2=a^2-2ab+b^2$ and $(a-b)(a+b)=a^2-b^2$ .

$\dfrac{k}{x-2}\times \dfrac{(x-2)^2}{(x-1)(x+1)}=\dfrac{5(x-2)}{x-1}$

$\dfrac{k(x-2)}{(x-1)(x+1)}=\dfrac{5(x-2)}{x-1}$

Cancel out the common factors from both sides.

$\dfrac{k}{x+1}=5$

Multiply both sides by (x+1).

$k=5(x+1)$

Therefore, the missing value is 5(x+1).

5 0

4 years ago

57 is greater than x - 8

svlad2 [7]

This is an inequality.

This is what the statement should look like: $57 > x - 8$

Now, you can actually "properly" reverse these meaning the equality sign changes too. So basically you can mirror them.

The "mirrored" inequality expression would look like this: $x - 8 < 57$

Now just like normal algebra, you can transpose these terms from 1 side to another and so, -8 would transpose to the right hand side and the operation would be the inverse or in this case, addition. The expression would look something like this: $x < 57 + 8$