1s^2 2s^2 2p^6 3s^2 2p^3 or the shortcut way is [Ne] 3s^2 2p^3
Answer:
17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.
Explanation:
We have:
Molarity of the NaCl solution = 6.32 M
Volume of the NaCl solution = 2,719 mL =2,719 × 0.001 L= 2.719 L
1 mL = 0.001 L
Let the moles of NaCl be n.
17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.
Due to the tilt of the earth
The condition of 273 K and 1.00 atm can be called STP. Under STP, there is a rule for gas that 22.4 L volume per 1 mole gas. So the volume is 33.6 L.
Answer:
0.1593 L.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and P are constant, and have two different values of V and T:
<em>P₁V₁T₂ = P₂V₂T₁</em>
<em></em>
P₁ = 600 torr/760 = 0.789 atm, V₁ = 185.0 mL = 0.185 L, T₁ = 25.0°C + 273 = 298.0 K.
P₂ (at STP) = 1.0 atm, V₂ = ??? L, T₂ (at STP = 0.0°C) = 0.0°C + 273 = 273.0 K.
<em>∴ V₂ = P₁V₁T₂/P₂T₁</em> = (0.789 atm)(0.185 mL)(298.0 K)/(1.0 atm)(273.0 K) = <em>0.1593 L.</em>
