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marshall27 [118]
3 years ago
10

A 1.85 kg textbook is sitting on a bookshelf 2.23 m above the floor. How much potential energy does it have?

Chemistry
1 answer:
neonofarm [45]3 years ago
7 0

Answer:

\boxed {\boxed {\sf 40.4299 \ Joules}}

Explanation:

Potential energy is energy due to position. It is the product of mass, height, and acceleration due to gravity.

PE= m \times g \times h

The mass of the textbook is 1.85 kilograms. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 2.23 meters.

  • m= 1.85 kg
  • g= 9.8 m/s²
  • h= 2.23 m

Substitute the values into the formula.

PE = 1.85 \ kg \times 9.8 \ m/s^2 \times 2.23 \ m

Multiply the first 2 numbers together.

PE=18.13 \ kg*m/s^2 *2.23 \ m

Multiply again.

PE= 40.4299 \ kg*m^2/s^2

  • 1 kilogram square meter per square second (1 kg*m²/s²) is equal to 1 Joules (J)
  • Our answer of 40.4299 kg*m²/s² is equal to 40.4299 J

PE= 40.4299 \ J

The textbook has <u>40.4299 Joules of potential energy.</u>

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How many liters of oxygen gas (O2) are needed to produce 100 kJ of energy at STP? 2C6H6(I) + 1502(g) —&gt; 12CO2(g)+6H2O(g)+3909
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Answer: 8.59 L of oxygen gas are needed to produce 100 kJ of energy at STP

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According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

Standard condition of temperature (STP)  is 273 K and atmospheric pressure is 1 atmosphere respectively.  

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The balanced chemical reaction is:

2C_6H_6(I)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(g)

3909.9 kJ of of energy is produced by  = 15\times 22.4=336L

100 kJ of oxygen gas are needed to produce = \frac{336}{3909.9}\times 100=8.59L

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A gas containing 80% CH4 and 20% He is sent through a quart/ diffusion tube (see Figure P8.8) to recover the helium, Twenty perc
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For a gas containing 80% CH4 and 20% He is sent through a quart diffusion tube, the composition is mathematically given as

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<h3>What is the composition of the waste gas if 100 kg moles of gas are processed per minute?</h3>

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%CH4=87.5%

Read more about Chemical reaction

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