These are the answers for the first 2 questions
<em></em>
<em>1.</em> 16.956 m
<em><u> formula:</u></em> C = 2πr
C = 2(3.14)(2.7)
C = 6.28(2.7)
C = 16.956
<em>4.</em> 15.7 ft.²
<u><em>formula:</em></u> C = πd
C = 3.14(5)
C = 15.7
From my research on the internet, the image attached supports this problem. The two lines are parallel, as supported by the converse of corresponding angles postulate. It states that:<span> If a </span>transversal<span> intersects two lines and the corresponding angles are </span>congruent<span>, then the lines are parallel.</span>
It should be the third one
Answer:
An equation
Step-by-step explanation:
If the sides of the rectangle are a and b,
Area=ab=3200^2
If the side with a ft cost $2/ft and side with bft costs $2/ft
Then,
Cost = 2*2*a+2*1*b=4a+2b
At minimum cost (or critical point), the derivative of cost =0
From area, b=3200/a
Using cost equation
C=4a+2*3200/a=4a+6400/a
First derivative with respect to a;
C'(a)=4-6400/a^2=0
Then, a=+/-40 The negative value is rejected. Therefore, a=40 ft and b=3200/40= 80 ft.
Therefore, a=40 ft and b=80 ft to minimize the fencing cost.
