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2 years ago

13 is 50% of what number

Mathematics

2 answers:

KiRa [710]2 years ago

5 0

The answer to your question is 26

andre [41]2 years ago

3 0

26. Hope this helped you :)

You might be interested in

27=3 raised to power (2x_1)

Ivahew [28]

Answer:

x = 2

Step-by-step explanation:

$27=3^{2x-1}\\\\3^{3}=3^{2x-1}\\$

Bases are equal. So, compare powers

2x - 1 = 3

Add 1 to both sides,

2x = 3+1

2x = 4

Divide both sides by 2

x = 4/2

x = 2

7 0

2 years ago

Pam and her brother both open savings accounts. Each begin with a balance of zero dollars. For every two dollars that Pam save i

dezoksy [38]

Answer:

Ratio [Pam to her brother] = 2:5

Step-by-step explanation:

Given:

Pam saves every two dollar

Her brother saves fives dollar (For every two dollar)

Find:

Ratio [Pam saving and his brothers saving]

Computation:

It is given that if Pam saves $2 her brother saves $5

So,

Ratio [Pam to her brother] = 2/5

Ratio [Pam to her brother] = 2:5

6 0

3 years ago

A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while

ki77a [65]

Answer:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=12$ represent the population standard deviation

n represent the sample size

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is $\alpha=1-0.96 =0.04$ . And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got $z_{\alpha/2}=2.054$ , replacing into formula (b) we got: