Answer: Option 'c' is correct.
Step-by-step explanation:
Since we have given that
the optimized solution of a linear program to an integer as it does not affect the value of the objective function.
As if we round the optimized solution to the nearest integer, it does not change the objective function .
while it is not true that it always produces the most optimal integer solution or feasible solution.
Hence, Option 'c' is correct.
To find the area of a square with it's diagonal, there's actually a formula = (1/2)d², but here's how to do it if you don't have the formula:
The diagonal <em>c</em> separates the square into two of the same triangles. Therefore, we can apply Pythagorean Theorem
a²+b²=c² ← Since this is a square, a=b is a must
a²+a²=c² ← Combine like terms, and plug 26 in for c
2a²= 26² ← 26²=676, then divide 2 on both sides
a²= 676/2
a²=338 ← We can just stop here! Since <em>a </em>is a side of the square, therefore the area of a square = a²
Answer: 338 units²
Answer: 1) The value of the 3 in option A is 10x the value of the 3 in option B
2) Option A has the 3 in the ones places, Option B has the 3 in the tenths place
Step-by-step explanation: