Answer:
Step-by-step explanation:
See the attached picture for explanation.
Answer:
Step-by-step explanation:
From the information given,
Number of personnel sampled, n = 85
Mean or average = 6.5
Standard deviation of the sample = 1.7
We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.
For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.
z×standard deviation/√n
= 1.96 × 6.5/√85
= 1.38
The confidence interval for the mean number of years spent before promotion is
The lower end of the interval is 6.5 - 1.38 = 5.12 years
The upper end is 6.5 + 1.38 = 7.88 years
Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years
Answer:
7:35
Step-by-step explanation:
we take the 35 and 45 and add it together, then take out the 60 minutes and put that in as an hour. the practice is two hours long plus the hour we took out. then the remaining minutes are 20. we add 20 minutes and three hours
Step-by-step explanation:
Since d is an decimal, the higher the power of d, the smaller the value.
Slope = (Y2 - Y1) / (X2 - X1)
Slope = (5 - 3) / (5 - 8) = 2/-3 = -2/3
Answer: (B) -2/3
