Solve the system algebraically. 2x + y - 10 = 0 x - y - 4 = 0 What is the value of y? 1/3 2/3 14/3

Mathematics

2 answers:

natima [27]3 years ago

8 0

To solve the system

$\left\{\begin{array}{c} 2x+y-10=0 \\ x-y-4=0 \end{array}\right.$

you have to add both equations:

$2x+y-10+x-y-4=0+0,\\ 3x-14=0,\\ 3x=14,\\ \\x=\dfrac{14}{3}$ .

Substitute this x-value into second equation:

$\dfrac{14}{3} -y-4=0,\\ y=\dfrac{14}{3} -4=\dfrac{14-12}{3}=\dfrac{2}{3}$ .

The solution of the system is x=14/3 and y=2/3.

Answer: y=2/3, correct choice is B.

lapo4ka [179]3 years ago

5 0

Answer:

2/3

Step-by-step explanation:

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2 years ago

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Vinil7 [7]

The answer is : B. (X-10)(x-4)

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4 years ago