Without that value, we can't solve your problem, unless you are looking for an algebraic equation.
Answer:
10 and 40 I think maybe?
Step-by-step explanation:
I hope this is correct if not I am so so so so so so sorry
Answer:
If all you care about is whether you roll 2 or not, you get a Binomial distribution with an individual success probability 1/6. The probability of rolling 2 at least two times, is the same as the probability of not rolling 2 at zero or one time.
the answer is, 1 - bin(k=0, n=4, r=1/6) - bin(k=1, n=4, r=1/6). This evaluates to about 13%, just like your result (you just computed all three outcomes satisfying the proposition rather than the two that didn’t).
Step-by-step explanation:
Answer:
3.14
Step-by-step explanation:
Given that:
Mean weight (m) = 79 ounces
Population standard deviation (s) = 13.1
Sample size = 47
Maximal margin of error associated with 90% confidence interval.
The margin of error is given by:
Zcritical * (standard deviation / sqrt(sample size)
Z critical at 90% confidence interval = 1.645
Hence,
Zcritical * (standard deviation / sqrt(sample size)
1.645 * 13.1 / sqrt(47)
1.645 * (13.1 / 6.8556546)
1.645 * 1.9108313
Hence, the margin of error is :
3.1433174885
= 3.14
Answer:
49.98
Step-by-step explanation: