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Lera25 [3.4K]
2 years ago
15

Find the circumference

Mathematics
2 answers:
tia_tia [17]2 years ago
7 0

Answer:

6.25\pi

Step-by-step explanation:

A circumference of a circle can be determined by this: 2*pi*r

We're given the diameter. Divide that by 2 to get the radius.

6.45/2 = 3.225

Now multiply that by 2*pi. That gives us 2 * 3.14 * 3.225 = 20.253.

This could've also been done easier by doing pi*d where d is the diameter and you give the answer by multiplying them both. Also works, but the above formula is just key to many things and can also be used to derive the simpler one. Hope it helps! :)

ch4aika [34]2 years ago
7 0

Answer:

6.45π OR 20.253 units.

Step-by-step explanation:

Given, Diameter (d) = 6.45 units

Circumference = πd = 6.45π

If, π = 3.14, then,

6.45π

= 6.45 * 3.14

= 20.253 units

Hope it helps ⚜

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Answer:

x = 135°

Step-by-step explanation:

6 sided polygon = hexagon

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⇒ 4x + 90 + 90 = 720

⇒ 4x = 720 - 90 - 90

⇒ 4x = 540

⇒ x = 540 ÷ 4

⇒ x = 135°

4 0
2 years ago
What is the angles mSRW?
Scilla [17]

Answer:

126°

Step-by-step explanation:

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18 = x

therefore, (3x)° = (3*18)°= (54)°

m\angle SRW + (3x)\degree = 180\degree \\m\angle SRW + 54\degree  = 180\degree \\m\angle SRW = 180\degree  - 54\degree  \\\huge\red{\boxed{m\angle SRW = 126\degree}}

5 0
3 years ago
14.7 divided by 2.2=
GenaCL600 [577]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Which number will have the same result when rounded to the nearest ten or hundred A-97 B-118and5 C-179 D-5091
slamgirl [31]
Lets round it to the nearest ten
A 97 ====> 100
B 118 ===> 120
C 179 ===> 180
D 5091 ==> 5090
No result yet, lets round to the nearest hindred.
A 97 ====> 100
B 118 ===> 100
C 179 ===> 180
D 5091 ==> 5100
As we can see only A give the same result when we round it to the nearest hundred and nearest ten.

5 0
3 years ago
Can someone please help me with these questions?
Dmitrij [34]

Expanded form is writing out everything and no simplifying.

A. c times c

B. t times t times t times t  

C. 2 times x times x times x  

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Hope this helps :)

8 0
3 years ago
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