Answer:
The probability that Joe's stock will go up and he will win in the lottery is 0.00005.
Step-by-step explanation:
Let the events be denoted as:
<em>X</em> = the stock goes up
<em>Y</em> = Joe wins the lottery
Given:
P (X) = 0.50
P (Y) = 0.0001
The events of the stock going up is not dependent on the the event of Joe winning the lottery.
So the events <em>X</em> and <em>Y</em> are independent of each other.
Independent events are those events that can occur together at the same time.
The joint probability of two independent events <em>A</em> and <em>B </em>is,
Compute the value of P (<em>X ∩ Y</em>) as follows:
Thus, the probability that Joe's stock will go up and he will win in the lottery is 0.00005.
That statement would be best express by " x + 25 < 75 ". Since the statement says the sum of x and 25, thus, it will be x + 25. Then it also states that the sum is less than 75, so the best expression would be " < 75".
Answer:
H0 : μ1 - μ2 = 0
H1 : μ1 - μ2 ≠ 0
-1. 34
0.1837
Step-by-step explanation:
Full time :
n1 = 125
x1 = 2.7386
s1 = 0.65342
Part time :
n2 = 88
x2 = 2.8439
s2 = 0.49241
H0 : μ1 - μ2 = 0
H1 : μ1 - μ2 ≠ 0
Test statistic :
The test statistic :
(x1 - x2) / sqrt[(s1²/n1 + s2²/n2)]
(2.7386 - 2.8439) / sqrt[(0.65342²/125 + 0.49241²/88)]
−0.1053 / sqrt(0.0034156615712 + 0.0027553)
-0.1053 /0.0785554
= - 1.34
Test statistic = - 1.34
The Pvalue :
Using df = smaller n - 1 = 88 - 1 = 87
Pvalue from test statistic score ;
Pvalue = 0.1837
Pvalue > α ; We fail to reject the null and conclude that the GPA does not differ.
At α = 0.01 ; the result is insignificant
Answer:
89
Step-by-step explanation:
7^2=49
49+4=53
6^2=36
53+36=89
Multiplying exponents with like bases is the same as adding up the exponents.
<span>(g^6)(g^11)=g^17
Hope this helps!</span>
