To simplify rational expressions, simply see and check if there is a common number or same number that can be divided from in both. If not here, you would simply multiply the numbers together.

Then simplify if you would need to.

It would be 85x/6

8 0

2 years ago

What is the square root of 5 divided by the square root of 15 and simplify and in fraction form

ozzi

Answer:

$\sqrt{\frac{1}{3} }$

$\frac{\sqrt{3} }{3}$

Step-by-step explanation:

The expression $\frac{\sqrt{5} }{\sqrt{15} }$ can be simplified by first writing the fraction under one single radical instead of two.

$\frac{\sqrt{5} }{\sqrt{15} } = \sqrt{\frac{5}{15} }$

5/15 simplifies because both share the same factor 5.

It becomes $\sqrt{\frac{5}{15} } = \sqrt{\frac{1}{3} }$

This can simplify further by breaking apart the radical.

$\sqrt{\frac{1}{3} } = \frac{\sqrt{1} }{\sqrt{3} } = \frac{1}{\sqrt{3} }$

A radical cannot be left in the denominator, so rationalize it by multiplying by √3 to numerator and denominator.

$\frac{1}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} } =\frac{\sqrt{3} }{3}$

4 0

2 years ago

Complete this section.

choli [55]

look at the attached picture

Hope it will help you

Good luck on your assignment

3 0

2 years ago

Read 2 more answers

The temperature of coffee served at a restaurant is normally distributed with an average temperature of 160 degrees Fahrenheit a

posledela

Answer:

The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 160 degrees

Standard Deviation, σ = 5.4 degrees

We are given that the distribution of temperature of coffee is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.2

$P( X < x) = P( z < \displaystyle\frac{x - 160}{5.4})=0.2$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 160}{5.4} = -0.842\\\\x = 155.4532$

Thus,

$P_{20}=155.4532$

The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.

7 0

2 years ago