Answer:
The proportion of people who were caught after being on the 1010 Most Wanted list would be 40.81%.
Step-by-step explanation:
Since the FBI wants to determine the effectiveness of their 1010 Most Wanted list, and to do so, they need to find out the fraction of people who appear on the list that are actually caught, supposing a sample of 517517 suspected criminals is drawn, and of these people, 211211 were captured, to estimate the proportion of people who were caught after being on the 1010 Most Wanted list using this data, the following calculation must be performed:
517,517 = 100
211,211 = X
211,211 x 100 / 517,517 = X
21,121,100 / 517,517 = X
40.81 = X
Therefore, the proportion of people who were caught after being on the 1010 Most Wanted list would be 40.81%.
Answer:
72
Step-by-step explanation:
9/11 = ?/88
<em>multiply each side by 8 (because 88 divided by 11 is 8)</em>
72/88 = ?/88
<em>multiply each side by 88</em>
72 = ?
Easy peasy
just subsitute I(x) for the x in the h(x) so
h(I(s))=-(2s+3)^2-4
distribute and simplify
h(I(s))=-(4s^2+12s+9)-4
h(I(s))=-4s^2-12s-9-4
h(I(s))=-4s^2-12s-13
