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neonofarm [45]
3 years ago
13

The "normal" high temperature for a June day in Albemarle is $82^\circ$ (degrees Fahrenheit). Last year, the first ten days of J

une were unusually hot, with highs of $84^\circ,$ $88^\circ,$ $91^\circ,$ $92^\circ,$ $96^\circ,$ $94^\circ,$ $89^\circ,$ $78^\circ,$ $87^\circ,$ and $81^\circ$. How many degrees above normal was the average high for that 10-day period?
Mathematics
1 answer:
crimeas [40]3 years ago
8 0

Answer:

6° F

Step-by-step explanation:

To get average of 10 days highs, we need to add all and divide by 10.

Average = \frac{84+88+91+92+96+94+89+78+87+81}{10}\\=\frac{880}{10}\\=88

And, the normal high temp is given as 82.

<em>How much higher is 88 than 82??</em>

<em />

It is 88 - 82 = 6°F above

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Answer:

Step-by-step explanation:

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Assume that the weight loss for the first month of a diet program varies between 6 pounds and 14 pounds, and is spread evenly ov
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Hello!

For this uniform distribution, the shape of the density function is a line. We can begin by identifying key elements of the distribution:

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1)

P(x = 7)

A uniform distribution is a continuous distribution, so the probability of x being an EXACT value is approximately 0.

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2)
We can think of this as finding the area of a rectangle.

The width would be the difference between 8.25 pounds and 12 pounds:
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The height would be the function (y = .125), or:
h = .125

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3)
To find the probability GREATER than 10.50 pounds, we can subtract this value from the max value for the width:
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5 0
2 years ago
Solve to get the value of h
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The answer to the question is h=64 degrees
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