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neonofarm [45]
4 years ago
13

The "normal" high temperature for a June day in Albemarle is $82^\circ$ (degrees Fahrenheit). Last year, the first ten days of J

une were unusually hot, with highs of $84^\circ,$ $88^\circ,$ $91^\circ,$ $92^\circ,$ $96^\circ,$ $94^\circ,$ $89^\circ,$ $78^\circ,$ $87^\circ,$ and $81^\circ$. How many degrees above normal was the average high for that 10-day period?
Mathematics
1 answer:
crimeas [40]4 years ago
8 0

Answer:

6° F

Step-by-step explanation:

To get average of 10 days highs, we need to add all and divide by 10.

Average = \frac{84+88+91+92+96+94+89+78+87+81}{10}\\=\frac{880}{10}\\=88

And, the normal high temp is given as 82.

<em>How much higher is 88 than 82??</em>

<em />

It is 88 - 82 = 6°F above

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Answer:

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Step-by-step explanation:

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3 years ago
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What is the slope of the line represented by the equation y = 4/5 x -3? A-1 B-4/5 C4/5 D3
Cerrena [4.2K]

Option C

<u>ANSWER: </u>

For the given equation slope is \frac{4}{5} so the correct option is c.

<u>SOLUTION: </u>

Given, line equation is $y=\frac{4}{5} x-3$

We need to find the slope of the given equation.

Above given equation is in the form of slope intercept form, i.e. y = mx + c

Where m is the slope and c is the intercept made on axis by this line.

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