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AleksandrR [38]
3 years ago
7

A salesman sold twice as much pears in the afternoon than in the morning. If he sold 360 kilograms of pears that day, how many k

ilograms did he sell in the morning and how many in the afternoon
Mathematics
1 answer:
serg [7]3 years ago
6 0

Answer: 240 kg

Step-by-step explanation: Divide 360 by 3. That would equal 120. 120 times 2 equals 240

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Solve this problem please <br> x/3+6-2x=-6
Nikolay [14]

Answer:

36/5

Step-by-step explanation:

x/3 + 6 -2x = -6

multiply the whole equation by 3 to get rid of the denominator of the first x term.

x+18-6x = -18

move x terms to one side and numerical terms to the other, subtract 18 from both sides in this case

x+18-6x-18=-18-18

x-6x = -36

simplify

-5x = -36

divide both sides by -5 to isolate x

x = -36/-5

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3 0
3 years ago
Greatest to least 1/3 1/2 3/4
schepotkina [342]
The answer will be 3/4, 1/2, and 1/3.
The bigger the fraction the smaller it is.
So 3/4 would be first .
The smaller the fraction the bigger it is.
So 1/3 would be last.
So that leaves you with 1/2 so that one would be in the middle of the set.
So the answer would be...:3/4, 1/2, and 1/3.
Hope that helped.
4 0
3 years ago
The supplement of an angle is 50 less than 3 times its complement, find the measure of the angle
Lelechka [254]

Answer:

20^{\circ}.

Step-by-step explanation:

Two angles are supplements of one another if their sum is 180^{\circ}.

Two angles are complements of one another if their sum is 90^{\circ}.

Let x^{\circ} be the measure of the angle in question.

The supplement of this angle would be (180 - x)^{\circ}.

The complement of this angle would be (90 - x)^{\circ}.

According to the question:

(180 - x) + 50 = 3\, (90 - x).

Solve this equation for x:

x = 20.

Thus, this angle would measure should 20^{\circ}.

The supplement of this angle would measure (180 - 20)^{\circ} = 160^{\circ}. The complement of this angle would measure (90 - 20)^{\circ} = 70^{\circ}.

Three times the complement of this angle would be 3 \times 70^{\circ} = 210^{\circ}, which is indeed 50^{\circ} greater than the supplement of this angle.

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2 years ago
ITS URGENT
Vinvika [58]

log.8 (.4096) =4

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loga b =c

a^c =b

8 0
3 years ago
What is the domain of y = -2x^(2)+ 8x
Vaselesa [24]
The domain is (-inf,+inf) and the range is (-inf,8]
5 0
2 years ago
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