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tangare [24]
3 years ago
12

Help ASAP please now please don’t comment unnecessary

Mathematics
1 answer:
Georgia [21]3 years ago
3 0

Answer:

Hope that helps!!

18.84x

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What is the base (in inches) of a triangle with an area of 161 square inches and a height of 14 inches?
pantera1 [17]

\textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh ~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ h=14\\ A=161 \end{cases}\implies 161=\cfrac{1}{2}b(14) \\\\\\ 161=7b\implies \cfrac{161}{7}=b\implies 23=b

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2 years ago
Plz help i have 9 min and i dont understand plz help worth 20 points
saw5 [17]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Please help!!!!! It's urgent
Evgesh-ka [11]
       2b                     2a
----------------- +  -----------------
   (b+a)^2            (b^2 - a^2)

            2b                     2a
= ----------------- +  -------------------
      (b+a)(b+a)         (b+a)(b-a)

         2b(b - a) +  2a(b + a)
= ------------------------------------
           (b+a)(b+a)(b-a)


         2b^2 - 2ab  +  2ab + 2a^2
= ---------------------------------------
           (b+a)(b+a)(b-a)

         2b^2 + 2a^2
= ------------------------
        (b+a)(b+a)(b-a)

         2(b^2 + a^2)
= ------------------------
        (b+a)^2 (b-a)

Answer:

Numerator:        2(b^2 + a^2)
Denominator:    (b+a)^2 (b-a)
7 0
3 years ago
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