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Firdavs [7]
3 years ago
7

The sum of -2x 2 + x + 31 and 3x 2 + 7x -8 can be written in the form ax 2 + bx + c , where a, b, and c are constants. What is t

he value of a+b+c?
Mathematics
1 answer:
storchak [24]3 years ago
5 0

Answer:

hey try looking it up on hooda math answers .com

Step-by-step explanation:

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The smiths have two children. The sum of their ages is 23. The produce of their ages is 132. How old are the children?
kolezko [41]

For this case we propose a system of equations:

x: Let the variable representing the age of the first child of the Smiths

y: Let the variable representing the age of the second child of the Smiths

According to the data of the statement we have to:

x + y = 23\\x * y = 132

From the first equation we have to:

x = 23-y

We substitute in the second equation:

(23-y) * y = 132\\23y-y ^ 2 = 132\\y ^ 2-23y + 132 = 0

We find the solutions by factoring:

We look for two numbers that, when multiplied, result in 132 and when added, result in 23. These numbers are 11 and 12.

Thus, we have that the factorized equation is:

(y-11) (y-12) = 0

Thus, the solutions are:y_ {1} = 11\\y_ {2} = 12

So, we can take any of the solutions:

With y = 11

Thenx = 23-11 = 12

Therefore, the ages of the children are 11 and 12 respectively.

Answer:

 The ages of the children are 11 and 12 respectively.

6 0
3 years ago
Find the Quotient.<br>2,874 - 4​
Tanya [424]

Answer:

718.5

Step-by-step explanation:

First, you see how many times 4 can go into 28. Then divide by 74. To get 718.5

3 0
3 years ago
If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
3 years ago
Need heals please ❤️
Neko [114]

B: Even

B is the answer



8 0
3 years ago
Read 2 more answers
Write the repeating decimal as a fraction. -0.356 with 2 trailing repeating decimals plz help ill give branliest
Dafna11 [192]

Answer:

Fraction: 89/250

Percentage:35.6%

Step-by-step explanation:

5 0
4 years ago
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