There are different ways to solve a quadratic equation, the main ones that i'm thinking about right now are:
1) factor the equation as a product:
ex: x^2+ 4x + 3 =0
(x+3) (x+1) = 0
x=-3 and x=-1 are the solutions.
To find (x+p) and (x+q) you have to think that (p+q )have to be equal to the number that is multiplied by x, in my example it was 4 (3+1=4), (p times q) have to be equal to the last number of the quadratic equation, the one that is not multiplied by any x, that in my example is 3 (3 x 1= 3)
2) The other way to solve a quadratic function is by using a formula:
given: ax^2 +bx +c=0
x= (-b +/- <span>√(b^2 -</span> 4ac)) / 2a
ex: 3x^2 + 4x -2=0
x= (-4 +/- √16-4(3)(-2)) / 6= (-4 +/- √16+24)/6= (-4 +/- <span>√40) / 6
now there are 2 possibilities: x= (-4+</span><span>√40) /6
and
x= (-4 - </span><span>√40) / 6
I hope the examples were clear enough also if i did't get very nice numbers. Look closely to the sings + and -, they are very important</span>
Answer:
Step-by-step explanation:
Switch sides:
Add/Subtract the numbers: 
Hope I helped, if so may I get brainliest and a thanks?
Thank you, have a good day! =)
Both of the other angles are 40° because a triangle has a total angle of 180° and an isosceles triangle means that at least two of the sides have to be the same length (two angles must be the same)
180 - 100= 80
80 ÷ 2 = 40
Answer:
mean age of women
(x+y+z)/3=27
mean age of men
(x1+x2+x3+x4+x5+x6)/6=34
mean age of all people in the office
x+y+z=27*3=81
x1+...x6=34*6=204
so
mean age( x+y+z+x1+x2+..x6)/(3+6)=(27*3+34*6)/9
=(81+204)/9=285/9=32 approximately
